Question

Which expression is equivalent to log Subscript 12 Baseline StartFraction x Superscript 4 Baseline StartRoot x cubed minus 2 EndRoot Over (x + 1) Superscript 5 Baseline EndFraction?
4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x times 1)


4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline StartFraction x cubed Over 2 EndFraction minus 5 log Subscript 12 Baseline 1


log Subscript 12 Baseline 4 x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x) + 1


4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x + 1)

Answer 1

Answer

D

 4logw (x^{2} - 6) - 1/3logw (x^{2} + 8)

Step-by-step explanation:

Answer 2

Answer:

(D)$4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)$

4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x + 1)

Step-by-step explanation:

Given the expression:

$log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}$

We first apply the division law of logarithm:$log_{a}x/y=log_{a}x-log_{a}y$

$log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}=log_{12}x^4\sqrt{x^3-2}-log_{12}(x+1)^5$

Next, by addition law: $log_{a}xy=log_{a}x+log_{a}y$

$=log_{12}x^4+log_{12}\sqrt{x^3-2}-log_{12}(x+1)^5\\\\Log a^m=mLog a, Log \sqrt{x}=log x^{1/2}\\\\ =4log_{12}x+log_{12}(x^3-2)^{1/2}-5log_{12}(x+1)\\\\=4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)$

The correct option is D.