3 years ago

Please help me with this one

Mathematics

1 answer:

Burka [1]3 years ago

7 0

What is the question

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Solve for x<br><br><br>answers. x=6<br> x=0. x=7

shtirl [24]

Answer:

X=0

Step-by-step explanation:

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Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5

Lesechka [4]

<h3>Answer: E) x^5</h3>

$\sqrt{x^{10}} = x^5$

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is $\sqrt{a^b} = a^{b/2}$

A more general rule is

$\sqrt[n]{a^b} = a^{b/n}$

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

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Which is the zero of the function f(x)=(x+3) (2x-1)(x+2) ?

Scrat [10]

Answer:

x= -3 x = 1/2 x=-2

Step-by-step explanation:

f(x)=(x+3) (2x-1)(x+2)

Set equal to zero

0 =(x+3) (2x-1)(x+2)

Using the zero product property

x+3 =0 2x-1 =0 x+2 =0

x= -3 2x =1 x = -2

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3 years ago