Answer:
Empirical formula is C₂H₄O
Explanation:
Given data:
Percentage of hydrogen = 9.15%
Percentage of carbon = 54.53%
Percentage of oxygen = 36.32%
Empirical formula of butyric acid = ?
Solution:
Number of gram atoms of H = 9.15 / 1.01 = 9.1
Number of gram atoms of O = 36.32 / 16 = 2.27
Number of gram atoms of C = 54.53 / 12 = 4.54
Atomic ratio:
C : H : O
4.54/2.27 : 9.1/2.27 : 2.27/2.27
2 : 4 : 1
C : H : O = 2 : 4 : 1
Empirical formula is C₂H₄O.
Answer: ≈ 67.4 g
Explanation:
A(t) = amount remaining in t years = A0ekt, where A0 is the initial amount and k is a constant to be determined. Since A(1690) = (1/2)A0 and A0 = 80, we have 40 = 80e1690k 1/2 = e1690k ln(1/2) = 1690k k = -0.0004 So, A(t) = 80e-0.0004t Therefore, A(430) = 80e-0.0004(430) = 80e-0.172 ≈ 67.4 g
Answer:
Explanation:
The number of moles is given by dividing the total number of molecule of water by the Avogradro's Number:
The unit of 16.8 /kjg contains a mistake.
I just can help you by assuming the right units.
I will assume 16.8 kj /g. This is a rate, which means that 1 g of reactant will produce 16.8 kj of heat.
To calculate the mass of reactant that will produce 800j first you multiply by the conversion factor to obtain kj, and the you divide by the rate of heat, 16.8 kj/g
heat * conversion factor / rate
(800j) * (1kj/1000j) / (16.8 kj / g) <--- answer