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vovangra [49]
2 years ago
14

Is it possible to start with 5g of one chemical and 10g of another chemical and make 15g of a third chemical?

Chemistry
1 answer:
antiseptic1488 [7]2 years ago
3 0

Answer : No

Explanation: The chemical compounds are formed from their elements in a fixed ratio of masses, for example, in water (H2O), always Hydrogen and oxygen are combined in 1:8 by mass, i.e. with 1 g Hydrogen the Oxygen is 8 g, with 2 g Hydrogen the oxygen would be 16 g. So, there is a fixed ratio by masses.

If we were to react hydrogen with oxygen then it would again combine in 1:8 always. If we use 1 g Hydrogen with 10 g oxygen, all of the 1 g hydrogen would still react with 8 g oxygen and the third chemical formed water is 1+8 = 9 g and not 1+10 =11 g.

So, its generally not possible.

Also not all chemical reactions proceed to completion, i.e. there are always few reactant molecules left unreacted, for example the burning of candle is a chemical process where some of the lower part of wax is left behind. so, not always all of the reactants get converted to products.

Only if we have a special case where reactants react completely and you chose the masses of reactant exactly in the ratio they combine, then only the third chemica will have mass exactly equal to the sum of masses of all reactants taken at the start, like if we take hydogen 2g and oxygen 16 g then water is 2+16 = 18, because 2 will combine exactly with 16.

Hope the answer helps.

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This explains the line spectrum and not a continuous spectrum.

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3 years ago
How to know if you can heat a laboratory flask and other glassware?
AnnyKZ [126]

Answer:

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7 0
2 years ago
Use the mole concept to calculate the number of atoms that are in a 1.75-mol sample of CHCl3.
Fiesta28 [93]
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6 0
3 years ago
The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in
nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  

W_s = weight of solvent in g  

Mole fraction of CO_2 is = 3.6\times 10^{-4} i.e.3.6\times 10^{-4}  moles of CO_2 is present in 1 mole of solution.

Moles of solute (CO_2) = 3.6\times 10^{-4}

moles of solvent (water) = 1 - 3.6\times 10^{-4} = 0.99

weight of solvent =moles\times {\text {Molar mass}}=0.99\times 18=17.82g

Molality =\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020

Thus  approximate molality of CO_2 in this solution is 0.020 m

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3 years ago
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rusak2 [61]
I believe it is NaCl(aq) + H2O
5 0
3 years ago
Read 2 more answers
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