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Step2247 [10]
3 years ago
7

20 POINTS!!!! If eight is added to twice a number and the sum is multiplied by five result is the same as if the number is multi

plied by -8 and four is added to the product. What is the number?
Mathematics
1 answer:
Sauron [17]3 years ago
6 0
<h3><u>The value of x is equal to -2.</u></h3>

5(2x + 8) = -8x + 4

<em><u>Distributive property.</u></em>

10x + 40 = -8x + 4

<em><u>Add 8x to both sides.</u></em>

18x + 40 = 4

<em><u>Subtract 40 from both sides.</u></em>

18x = -36

<em><u>Divide both sides by 18</u></em>

x = -2

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How many years is tween 1844 to2015
STatiana [176]
To find the number of years between 1844 to 2015 you have to subtract.

Lets say that x is the # of years in between 1844 and 2015

Then we have:
\sf{2015 - 1844 =x}

After doing the subtraction using a calculator or a pencil and paper, you get that:

\huge{\boxed{\bf{x=171}}}

So 171 years have passed from 1844 to reach to 2015.
4 0
3 years ago
Read 2 more answers
Can someone please help me check my answers ***Mark Brainliest***
lozanna [386]
I believe the answer for 17 is C.  18 I am not sure how to do.  For 19, however, the answer is B.  Hope I help, and sorry I can't answer 18.
3 0
3 years ago
Please give an explanation as well as an answer :)
STatiana [176]

Answer: It is 10 because there are 2 other faces and 8+2=10

Step-by-step explanation:

3 0
2 years ago
C. Solve 1/2 x - (x+3)&lt;1/3(x-1)​
MAVERICK [17]

Answer: x = 28

Step-by-step explanation:

Let's solve your equation step by step!

3/8x + 15/2 = 18

Step 1: Subtract 15/2 from both sides.

3/8x + 15/2 - 15/2 = 18 - 15/2

3/8x = 21/2

Step 2: Multiply both sides by 8/3

(8/3) * (3/8x) = (8/3) * (21/2)

Step 3. Calculate

x = 28

7 0
2 years ago
If (x/100-1)(x/100+1)=kx^2-1 k=
Artist 52 [7]
(x/100-1)(x/100+1)=kx^2-1
(x/100-1)(x/100+1)=(x/100)^2 - 1^2 because it's a difference of squares ( (a-b)(a+b) = a^2-ab+ab-b^2 = a^2 - b^2):
(x/100)^2 - 1^2=kx^2 - 1
(x/100)^2 - 1=kx^2 - 1
(x/100)^2=kx^2
(x^2)/(100^2)=kx^2
1/(100^2)=k
1/10000=k
k=0.0001
3 0
3 years ago
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