Absolute value equations have more than one solution because when the answer is in abs. value, it is positive, so there could be a negative answer and it would still be positive. For example |-5|=5 and |5|=5 as well.
4+|2x|=-1 would have no solution because you cannot have the equation equal a negative since the 2x is in absolute value.
Answer:

Step-by-step explanation:
Given Equation:
Equation:1
Equation:2
Dividing Equation:2 by '3' both the sides:
or
Equation:3
Putting the vale of 'x' in Equation:1


Subtracting '3' both sides



Putting value of 'y' in Equation:3


The solution of the equations is :

The system of equations when been placed in a matrix yields
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the equation:
y = 650x + 175 and;
y = 25080 - 120x
Rearranging the equations gives:
650x - y = -175 and;
120x + y = 25080
Placing the equations in a matrix gives:
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
The system of equations when been placed in a matrix yields
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
Find out more on equation at: brainly.com/question/2972832
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Answer:
The volume of cone v= 113.04 cm³.
Step-by-step explanation:
Formula used to find volume of cone is:

where r is the radius and h is the height of cone.
In the given question we are given:
height h= 6 cm
diameter d= 6 cm
We know radius r = d/2 = 6/2 = 3 cm
so, volume will be:



So, the volume of cone v= 113.04 cm³ given height h= 6cm and radius r= 3cm