Answer:
all real numbers
Step-by-step explanation:
Answer:
y = -5/2
Step-by-step explanation:
hope this helps believe it is the right answer :D
Answer:
Step-by-step explanation:
(x) = (1100 + x) (100 - .05(x-1100))
This is a quadratic, graphs as a parabola that opens downward. A maximum cam be found.
The zeros of the function are
(1100 + x) = 0 ..... or ..... [100 - .05(x-1100)] = 0
x = -1100 is the left x-intercept.
[100 - .05(x-1100)] = 0
100 = .05(x-1100)
2000 = x - 1100
x = 3100 is the right intercept.
Maximization of profits is at the mid point of the zeros (x-intercepts)
(3100 + -1100)/2 = 1000
1100 + 1000 = 2100 trees should be planted to maximize profits.
f(x) = (1100 + 1000) (100 - .05(1000-1100))
f(x) = (2000) (105) = 220,500 is the maximum profit.
I hope this helps!
Answer:
La cantidad de dinero adeuda al final de los dos procesos es $1450
Step-by-step explanation:
Los parámetros del proceso son;
La cantidad ahorrada para comprar ropa = $2,000
La cantidad pagada por la ropa = $2600
La cantidad prestada a un amigo = $650
La cantidad adeuda por teléfono celular durante 3 meses = $250
Deje que 'C', represente la suma de las transacciones anteriores, tenemos;
∴ C = 2,000 - 2,600 - 650 - 200 = -1,450
La suma de las transacciones anteriores, C = -$1,450
Por lo tanto, al final de los dos procesos, la cantidad de dinero adeuda es C = $1,450
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