Answer:
Option 3 (7,2) is right answer.
Step-by-step explanation:
Given two equations
3x-2y=17 ... i
x-3y=1 ... ii
We can solve this by elimination.
coefficients of x are 3 and 1 with LCD = 3
Hence multiply ii equation by 3
3x-9y = 3 ... iv
3x-2y = 17 ... i
Subtract i from iv
-7y = -14
Divide by -7
y =2
Substitute in ii
x-3(2) = 1
x=7
Hence solution is (7,2)
Verify:
We can verify our solution by substituting in i and ii.
3(7)-2(2) = 17 and 7-6 =1
Verified
Well 2 4/5 in decimal form is 2.8 so that is the greatest, then 2.6 is the second and 2.3 is the least
2 4/5, 2.6, 2.3
124 sq in...................
When we do the additive inverse property...we want to end up with a 0...so the inverse of 7 is -7 and the inverse of -8 is +8....we now have our new expression
-7 + 8
-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----
-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8