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Answer:
0.4
Explanation:
Given data:
Number of moles of SrCl₂ consumed = ?
Mass of ZnCl₂ produced = 54 g
Solution:
Chemical equation:
ZnSO₄ + SrCl₂ → SrSO₄ + ZnCl₂
Number of moles of ZnCl₂:
Number of moles = mass/ molar mass
Number of moles = 54 g/136.3 g/mol
Number of moles = 0.4 mol
Now we will compare the moles of ZnCl₂ with SrCl₂ from balance chemical equation.
ZnCl₂ : SrCl₂
1 : 1
0.4 : 0.4
Thus when 54 g of ZnCl₂ produced 0.4 moles of SrCl₂ react.
Answer:
B.) 2.92
Explanation:
Tp find the mass of H₂ produced, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass), then (2) convert moles AlCl₃ to moles H₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂ to grams H₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.
Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)
Molar Mass (AlCl₃): 133.341 g/mol
2 Al + 6 HCl ---> 2 AlCl₃ + 3 H₂
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
129 g AlCl₃ 1 mole 3 moles H₂ 2.016 g
------------------ x ------------------ x --------------------- x --------------- =
133.341 g 2 moles AlCl₃ 1 mole
= 2.93 g H₂
*our answers are most likely different due to using slightly different molar masses
The moles of KClO₃ that were consumed is 0.343 moles
<u><em>calculation</em></u>
2KClO₃ → 2KCl +3O₂
step 1: find the moles KCl
moles = mass÷ molar mass
25.6 g÷74.55 g/mol =0.343 moles
Step 2 : use the mole ratio to determine the moles KClO₃
from equation above KClO₃ : KCl is 2:2 =1:1
therefore the moles KClO₃ = 0.343 moles