All categories

3 years ago

- How does melting point compare among molecular compounds and ionic compounds?

Chemistry

1 answer:

GaryK [48]3 years ago

7 0

Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound (Figure 6.2. 1) .

Explanation:

hopefully this helps :)

if not then here. (Most of the time, the melting points of ionic compounds are very high compared to the melting points of molecular compounds.)

You might be interested in

Can sound pass through space?

Tresset [83]

Answer:

no it can not

Explanation:

6 0

3 years ago

Read 2 more answers

The liter is used to measure _____. weight mass volume length

Ket [755]

the answer to your question is

volume

4 0

4 years ago

Read 2 more answers

Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a

klio [65]

i have the same question idk the anwser tho

5 0

3 years ago

Which law states that the pressure and absolute temperature of a fixed quantity of gas are directly proportional under constant

Romashka [77]

Answer:

Gay-Lussac’s law

Explanation:

Gay-Lussac’s law is one of the gas laws discovered and proposed by a French scientist called Joseph Gay Lussac (1778 - 1850). In this law, it is stated that the pressure (P) of a gas varies directly with the absolute temperature (T) at a constant volume.

That is;

: P ∝ T

: P/T = K

Where:

P = pressure exerted by the gas

T = absolute temperature of the gas

K = the constant.

Hence, according to this question, the law that states that "the pressure and absolute temperature of a fixed quantity of gas are directly proportional under constant volume conditions" is Gay-Lussac’s law.

5 0

3 years ago

Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion

Kisachek [45]

Answer:

The likely magnitude of the equilibrium constant k for the reaction between hydrogen and oxygen is k>10³

Explanation:

The equilibrium constant k for the reaction 2H₂(g) + O₂(g)⇄ 2H₂O(g) can be expressed as follows

$K = \frac{[H_2O]^2}{[H_2]^2[O_2]}$

As the concentration of the products increase and concentration of the reagents decrease, the value of the equilibrium constant increases as well. The reaction between Hydrogen and Oxygen is violent, meaning that the concentration of the products will be high and the concentration of the reagents will be low. That's why the equilibrium constant has a likely magnitude of k>10³

4 0

3 years ago

Read 2 more answers