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3 years ago

If gold is selling presently for $1000.00/oz how much would 1 cubic inch of gold be worth?

Chemistry

1 answer:

KatRina [158]3 years ago

6 0

Answer:

$89.69

Explanation:

$1000 = 1 oz = 28.3g

volume = mass/density

volume = 28.3/19.3 = 1.47cm³

1 inch= 2.54 cm

1 cubic inch = (2.54)³ = 16.39 cm³

16.39/1.47 = 11.15 cubic inch

11.15 cubic inch = $1000

1 cubic inch = 1000/11.15 = $89.69

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How much positive charge is in 1.4 kg of oxygen? The atomic weight (15.9994 g) of oxygen contains Avogadro’s number of atoms, wi

Cerrena [4.2K]

Answer:

$6.7511\times 10^7\ C$

Explanation:

The atomic weight of oxygen = 15.9994 g

This mass corresponds to 1 mole of the oxygen atoms.

Thus,

15.9994 g mass of oxygen contains $6.02\times 10^{23}$ atoms of oxygen.

1.4 kg = 1400 g ( 1 kg = 1000 g)

So,

1400 g mass of oxygen contains $\frac {6.02\times 10^{23}}{15.9994}\times 1400$ atoms of oxygen.

Number of atoms in 1400 g of oxygen = $526.769754\times 10^{23}$

Also, 1 atom of oxygen contains 8 protons

Charge of 1 proton = + $1.602\times 10^{-19}\ C$

So, Charge on 1 atom of oxygen = $8\times 1.602\times 10^{-19}\ C$

Thus,

Charge on $526.769754\times 10^{23}$ atoms of oxygen = $526.94476\times 10^{23}\times 8\times 1.602\times 10^{-19}\ C=6.7533\times 10^7\ C$

Thus, positive charge in 1.4 kg of oxygen = $6.7511\times 10^7\ C$

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3 years ago

A substance has a mass of 100 g and a volume of 10 mL. What is the

Marysya12 [62]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$denstity = \frac{100}{10} \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

When a 32.3 g sample of NaI (Sodium Iodide) dissolves in 90.0 mL of water in a calorimeter, the temperature rises from 23.5 ℃ to

Leona [35]

Answer:

Explanation:

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3 years ago

How to calculate the frequency of an ion

sergij07 [2.7K]

solution:

You need to find the frequency, and they have already given you the wavelength. And since you already know the speed of light, you can use formula (2) to answer this problem. Remember to convert the nano meters to meters because the speed of light is in meters. $(1 nm = 1.0 x 10^{-9} m)$

$v=c\lambda \\v= (3.00 \times 10^8 m/s)/(6.9\times 10^-7 m) \\v = 4.35 \times 10^{14} s^{-1}$

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4 years ago

How many atoms are present in 3 moles of chromium?

Murljashka [212]

Answer:

1.80 x 10^24 atoms

Explanation:

3moles × 6.022×10^23 atoms/mole

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3 years ago