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3 years ago

Given the balanced equation:

Chemistry

1 answer:

Aliun [14]3 years ago

6 0

Answer:

0.4

Explanation:

Given data:

Number of moles of SrCl₂ consumed = ?

Mass of ZnCl₂ produced = 54 g

Solution:

Chemical equation:

ZnSO₄ + SrCl₂ → SrSO₄ + ZnCl₂

Number of moles of ZnCl₂:

Number of moles = mass/ molar mass

Number of moles = 54 g/136.3 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of ZnCl₂ with SrCl₂ from balance chemical equation.

ZnCl₂ : SrCl₂

1 : 1

0.4 : 0.4

Thus when 54 g of ZnCl₂ produced 0.4 moles of SrCl₂ react.

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Calculate the percent of composition of oxygen in Mercury (ll) oxide HgO

bekas [8.4K]

Add up the molar mass of Mercury Oxide, and then divide the molar mass of Oxygen by the molar mass of the compound.

So...

mm of Hg + mm of O= 200.59g + 16g= 217g

16g/217g = .0737... x 100 = 7.37%

6 0

3 years ago

What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?

Semmy [17]

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

8 0

3 years ago

If I started with 42.00 L of oxygen (O2) gas, how many grams is that?

belka [17]

Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

5 0

3 years ago

A cylinder contains 250 g of Helium at 200 K. The external pressure is constant at 1 atm. The temperature of the system is raise

Black_prince [1.1K]

Answer:

There is 96200 J or 96 kJ of heat released.

Explanation:

Step 1: Data given

Mass of helium = 250 grams

Temperature = 200 K

Temperature is raised by 74 K

The heat capacity of helium = 20.8 J/mol*K

Molecular weight for helium = 4 g/mol

Step 2: Calculate moles of Helium

Moles of Helium = mass of Helium / molar mass of helium

Moles of helium = 250 grams / 4g/mol

Moles of helium = 62.5 moles

Step 3: Calculate heat

Q = n*c*ΔT or

⇒ with Q = the heat released in Joule

⇒ with n = moles of helium = 62.5 moles

⇒ with c = the heat capacity of helium = 20.8 J/mol*K

⇒ with ΔT = the change in temperature = T2 - T1 = 74 K

Q = 62.5 mol * 20.8 J/mol*K * 74 K

Q = 96200 J = 96 kJ

Since the temperature is raised, this is an exothermic reaction. The heat is released.

There is 96200 J or 96 kJ of heat released.

8 0

3 years ago

The monovalent salt concentration (the predominant solute in the blood cell) for a sample of red blood cells is 0.13 moles/liter

11111nata11111 [884]

Answer:

The osmotic pressure of cell is $648.3$ KPa

Explanation:

As we know the osmotic pressure is equal to

$\pi = icRT$

Where

i is the Van Hoff factor

c is the concentration of solution

R is the ideal gas constant

and T is the temperature.

Substituting the given values, we get -

$\pi = 2 * 0.13 * 0.08206 * 300\\$

$\pi = 648.3$ KPa

4 0

3 years ago