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kodGreya [7K]
2 years ago
7

At what temperature do the gas and liquid phases become indistinguishable from each other?

Chemistry
2 answers:
sergiy2304 [10]2 years ago
5 0

Answer:

100 C or 212 F

Explanation:

That is the boiling point for liquid so both gas and liquid are presented.

mel-nik [20]2 years ago
5 0

Answer:

Depends on the liquid you're talking about

Explanation:

At the boiling point for a liquid is when the liquid becomes gas. For water it is 100 C

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Answer:

Gamma rays

Explanation:

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Which equation has both a liquid and a gas as products? 2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscri
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<h2>Let us predict the gas and liquid products in option </h2>

Explanation:

option  1 :  2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscript 2 (g).

Chemical reaction

It is the reactants react to form products .

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It is the method of representing reaction in terms of moles , specifying states , symbols , molecular formulas etc .

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The substance water always has a mass ratio of 11% H to 89% O. If 5.00g of a substance containing H and O was decomposed into .2
Gre4nikov [31]

Answer:

                    No the substance is not water.

Explanation:

                   The balance chemical equation for the decomposition of water is as follow;

                                           2 H₂O = 2 H₂ + O₂

Step 1: <u>Calculate moles of H₂O;</u>

               Moles  =  Mass / M.Mass

               Moles  =  5.0 g / 18.01 g/mol

               Moles  =  0.277 moles of H₂O

Step 2: <u>Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:</u>

According to equation,

                        2 moles of H₂O produced  =  1 mole of O₂

So,

                  0.277 moles of H₂O will produce  =  X moles of O₂

Solving for X,

                     X =  0.277 mol × 1 mol / 2 mol

                     X =  0.138 moles of O₂

Also,

According to equation,

                        2 moles of H₂O produced  =  2 mole of H₂

So,

                  0.277 moles of H₂O will produce  =  X moles of H₂

Solving for X,

                     X =  0.277 mol × 2 mol / 2 mol

                     X =  0.227 moles of H₂

Step 3: <u>Calculate Mass of O₂ and H₂ as;</u>

For O₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.138 mol × 31.99 g/mol

                 Mass  =  4.44 g of O₂

For H₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.227 mol × 2.01 g/mol

                 Mass  =  0.559 g of H₂

Conclusion:

                   From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.

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