Answer:-
The reaction of 2-bromopropane reacts with sodium iodide in acetone is an example of Sn2 reaction.
The I - attacks from backside to give the transition state for both.
If we compare the transition state for cyclobromopropane 2-bromopropane then we see in case of cyclobromopropane transition state, one of the H is very close to the incoming I -.
This results in steric strain and less stability of the transition state. Hence 2-bromopropane reacts with sodium iodide in acetone over 104 times faster than bromocyclopropane.
Answer:
See figure 1
Explanation:
If we want to find the acid and the Brønsted-Lowry base, we must remember the definition for each of these molecules:
-) Acid: hydrogen donor
-) Base: hydrogen acceptor
In the <u>caffeine structure,</u> we have several atoms of nitrogen. These nitrogen atoms have the ability to <u>accept</u> hydronium ions (
). Therefore the caffeine molecule will be the base since it can accept
If caffeine is the base, the water must be the acid. So, the water in this reaction donated a hydronium ion.
<u>Thus, caffeine is the base and water the acid. (See figure 1)</u>
Answer : The correct expression for equilibrium constant will be:
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
![4A+2B\rightleftharpoons 8C](https://tex.z-dn.net/?f=4A%2B2B%5Crightleftharpoons%208C)
The expression of
will be,
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Therefore, the correct expression for equilibrium constant will be, ![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,
![PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)](https://tex.z-dn.net/?f=PCl_3%28g%29%2BCl_2%28g%29%5Crightleftharpoons%20PCl_5%28g%29)
The expression of equilibrium constant
for the reaction will be:
![K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%28p_%7BPCl_5%7D%29%7D%7B%28p_%7BPCl_3%7D%29%28p_%7BCl_2%7D%29%7D)
Now put all the values in this expression, we get :
![K_p=\frac{(10.24)}{(0.348)(0.441)}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%2810.24%29%7D%7B%280.348%29%280.441%29%7D)
![K_p=66.7](https://tex.z-dn.net/?f=K_p%3D66.7)
Therefore, the value of
at this temperature is 66.7
1 N₂ + 3 H₂ = 2 NH₃
Mole ratio <span> of hydrogen to ammonia :
3 moles H</span>₂ : 2 moles NH₃ or 3 : 2
hope this helps!