Answer:
The final size is approximately equal to the initial size due to a very small relative increase of 
in its size
Solution:
As per the question:
The energy of the proton beam, E = 250 GeV =
Distance covered by photon, d = 1 km = 1000 m
Mass of proton, 
The initial size of the wave packet, 
Now,
This is relativistic in nature
The rest mass energy associated with the proton is given by:
This energy of proton is 
Thus the speed of the proton, v
Now, the time taken to cover 1 km = 1000 m of the distance:
T = 
T = 
Now, in accordance to the dispersion factor;
Thus the increase in wave packet's width is relatively quite small.
Hence, we can say that:
where
= final width
Answer:
The speed is 0.97 c.
Explanation:
Given that,
Dilated time t'= 50.0 years
Rest time t = 13.0 years
We need to calculate the speed
Using formula of time dilation
Where, t' = change in time
t = rest time
v = velocity
c = speed of light
Put the value into the formula
Hence, The speed is 0.97 c.
Need to draw it first.....
but there is no option here to draw .. why?
anyway , here the car is going with a uniform velocity..
so the acceleration of the car=0, a=0
so resistive force on the car=component along the inclined plane of the weight of the car=mg*cos(90-15)=960*9.8*cos 75=?
Length of the sheet is given as
width of the sheet is given as
now let say its thickness is "t"
so the volume of the sheet is given as
mass of the sheet is given as
now we have
by solving above we have
so the thickness of sheet will be above
Explanation:
The work done by an object is given by :
Here,
F is force
d is displacement
is the angel between F and d.
If the angle between force and displacement is 0, then the work done is equal to, 
.
So, a force does work on an object if a component of the force is parallel to the displacement of the object.
