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olganol [36]
3 years ago
14

Light and radio waves travel through a vacuum in a straight line at a speed of very nearly 3.00 ´ 108 m/s. How far is light year

(the distance light travels in a year)?
Physics
1 answer:
mezya [45]3 years ago
7 0
<span>We need to calculate the number of seconds in one year. time = (365 days) (24 hours/day) (3600 seconds/hour) time = 31536000 seconds We can calculate the distance that light travels in this many seconds. distance = speed x time distance = (3.00 x 10^8 m/s) (31536000 seconds) distance = 9.46 x 10^{15} meters A light year is 9.46 x 10^{15} meters</span>
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A chicken crosses a 7.50 m wide road at a constant speed of 0.367 m/s. How much time does it take to cross (in seconds)?
mars1129 [50]
<h3><u>Answer;</u></h3>

= 20.436 seconds

<h3><u>Explanation;</u></h3>

Speed = Distance × time

Therefore;

Time = Distance/speed

Distance = 7.50 m, speed = 0.367 m/s

Time = 7.50/0.367

         <u>= 20.436 seconds </u>

7 0
3 years ago
Read 2 more answers
A solid object has a mass of 104 kg and a volume of 1,278 m3. What is its density?
MrMuchimi
The density is 81.4 g/m3. Before you start plugging numbers into the density formula (D=M/V), you should convert 104 kg to grams, which ends up being 104,000 grams. Then you can plug in the 104,000 grams and 1,278 m3 into the formula. When you divide the mass by the volume, you get a really long decimal, which you can round to 81.4 g/m3, or whatever place your teacher wants you to round to.
4 0
3 years ago
A car with mass m traveling at speed v has kinetic energy k. what is the kinetic energy of a second car that has the same mass m
vampirchik [111]
Kinetic energy, KE, is modeled by the formula KE =  \frac{1}{2}mv^2, where m is the mass in kg and v is the velocity in m/s.

In this scenario, mass and one-half are constant but the velocity changes. 

You can see that by squaring twice the velocity, that is equal to four times the original KE. Therefore, the answer is 4k.
7 0
3 years ago
if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......25
NeX [460]

256 kPa because p-guage + p-absolute + p-atmospheric = 256

7 0
3 years ago
A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 1
Bumek [7]

Answer:

202.8m

Explanation:

Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.

First calculate the total time travelled by using the second equation of motion

h = Ut + 1/2gt^2

Let assume that u = 0

And h = 3.5

Substitute all the parameters into the formula

3.5 = 1/2 × 9.8 × t^2

3.5 = 4.9t^2

t^2 = 3.5/4.9

t^2 = 0.7

t = 0.845s

To know how far the cannonball travel, let's use the equation

S = UT + 1/2at^2

But acceleration a = 0

T = 2t

T = 1.69s

S = 120 × 1.69

S = 202.834 m

Therefore, the distance travelled by the cannon ball is approximately 202.8m.

4 0
2 years ago
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