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miv72 [106K]
3 years ago
7

You are on a ParKour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long wal

l. Lastly you traverse 15 meters of obstacles to reach the end of the course. The trip takes 43 seconds. What is your average speed?
Question 8 options:

0.65 m/s


1204 m/s


1.5 m/s


0.22 m/s
Physics
1 answer:
Svet_ta [14]3 years ago
8 0

The average speed would be  0.65 m/s, therefore the correct option is (A).

The average speed is calculated by the formula

Average speed= (total distance/ total time)

The total distance of the trip=9.5+3.5+15=28 m

The total time of trip=43 sec

Therefore the average speed=28/43=0.65 m/s.


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If the temperature of water warming on a hot plate rises 10 degrees Celsius [°C], what is the change in temperature in units of
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Answer:

Delta_temp = 18[°F]

Explanation:

°F = 9/5*(10)

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Suppose there are 10,000 civilizations in the Milky Way Galaxy. If the civilizations were randomly distributed throughout the di
vekshin1

Here is the full question

Suppose there are 10,000 civilizations in the Milky Way Galaxy. If the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization?

(Hint: Start by finding the area of the Milky Way's disk, assuming that it is circular and 100,000 light-years in diameter. Then find the average area per civilization, and use the distance across this area to estimate the distance between civilizations.)

Answer:

1000 light-years (ly)

Explanation:

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A = \pi (\frac{D}{2})^2

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d= \frac{A}{N} =\frac{\pi (\frac{D}{2})^2 }{10, 000}

The distance between each disk is further calculated by finding the radius of the density which is shown as follows:

d = \pi r^2 e

r^2_e= \frac{d}{\pi}

r_e = \sqrt{\frac{d}{\pi} }

replacing d = \frac{\pi (\frac{D}{2})^2 }{10, 000} in the equation above; we have:

r_e = \sqrt{\frac{\frac{\pi (\frac{D}{2})^2 }{10, 000}}{\pi} }

r_e = \sqrt{\frac{(\frac{D}{2})^2 }{10, 000}}

r_e = \sqrt{\frac{(\frac{100,000}{2})^2 }{10, 000}}

r_e = 500 ly

The distance (s) between each civilization = 2(r_e)

= 2 (500 ly)

= 1000 light-years (ly)

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