To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg.
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
Answer:
option D
Explanation:
given,
increase the intensity by factor of 9
I₁ = I₀
I₂ = 9 I₀
now,
A₂ = 3 A₁
hence, amplitude increase with the factor of 3
so, the correct answer is option D
Answer:
it would take rod B twice as much time
Explanation:
it would take rod B twice as much time as it is twice as thick and twice as long. Due to this reason it would take the electric charge not only more time but even more voltage to travel through the rod
QUESTION: A pure jet engine propels and aircraft at 340 m/s through air at 45 kPa and -13C. The inlet diameter of this engine is 1.6 m, the compressor pressure ratio is 13, and the temperature at the turbine inlet is 557C. Determine the velocity at the exit of this engines nozzle and the thrust produced.
ANSWER: Due to the propulsion from the inlet diameter of this engine bring 1.6 m allows the compressor rations to radiate allowing thrust propultion above all velocitic rebisomes.
Answer:
57 N
Explanation:
Force on a current carrying conductor in a magnetic field
B = 12 X 10⁻⁴ T
= Bil where B is magnetic field , i is current and l is length of conductor
force required = 12 x10⁻⁴ x 47500 x 1
= 57 N
