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3 years ago

A prism is filled with 60 cubes with 1/2 unite side length

1 answer:

3 0

Good good day to go back to work Tuesday morning babe I’m finna was your birthday day I love y’all and I’ll see y’all soon

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3. Each bangle printed by a 3D printer has a mass of exactly 25 g of metal. If the density of the metal is 14 g/cm3, what length

nadezda [96]

Answer:

57.0 cm

Step-by-step explanation:

We know that the radius of the filament is 1 mm. Taken to cm, is 0.1 cm.

From the density and mass, we can get the volumen of the bangle:

d = m/V ----> V = m/d

Solving for V:

V = 25 / 14 = 1.79 cm^3

We can assume that a bangle is a cylinder so:

V = π*r^2*h

1.79 = 3.14 * 0.1^2 * h

h = 1.79 / 3.14 * 0.01

h = 57.0 cm

5 0

3 years ago

I need help! It’s for a quiz I need an answer today please!

shutvik [7]

13.5•18 = 243 inches squared

5 0

3 years ago

Solve the formula -8x-3y=-19 for y

Ann [662]

Answer:y = (19 - 8x)/3

Step-by-step explanation:

add 8x to both sides ,

-3y = -19+8x

dividing both sides by -3

y = (19 - 8x)/3

7 0

4 years ago

train invest $203.50 in an account that earns 4.5% simple interest at the end of one year how much interest will trains investme

ivann1987 [24]

$203.50×0.045= $9.1575

$9.1575 + $203.50= $212.6575

$212.66

8 0

4 years ago

If an arrow is shot upward on Mars with a speed of 62 m/s, its height in meters t seconds later is given by y = 62t − 1.86t². (R

Soloha48 [4]

Answer:

Approximately $58.28\; \rm m \cdot s^{-1}$ .

Step-by-step explanation:

The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.

Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height: $y = 62\, t - 1.86\, t^2$ .

Apply the power rule to find the first derivative of this $y$ with respect to time $t$ .

By the power rule:

the first derivative of $t$ (same as
the first derivative of $t^2$ (same as $t$ to the second power) with respect to

Therefore:

$\begin{aligned}\frac{dy}{d t} &= \frac{d}{d t}\left[62 \, t - 1.86\, t^2\right] \\ &= 62\,\left(\frac{d}{d t}\left[t\right]\right) - 1.86\, \left(\frac{d}{d t}\left[t^2\right]\right) \\ &= 62 \times 1 - 1.86\times\left(2\, t) = 62 - 3.72\, t\end{aligned}$ .

In other words, the (vertical) velocity of this arrow at time $t$ would be $(62 - 3.72\, t)$ meters per second.

Evaluate this expression for $t = 1$ to find the (vertical) velocity of this arrow at that moment: $62 - 3.72 \times 1 =58.28$ .

6 0

3 years ago

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