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2 years ago

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Write an equation of each line with the given slope and y-intercept. slope = 1/2 y-intercept = 0

1 answer:

Novay_Z [31]2 years ago

8 0

Answer:

y = 1/2x

Step-by-step explanation:

hope this help you!! ;))

You might be interested in

Consider the expression? <br> Please help me !

Arada [10]

Answer:

sqrt(-8x+5)

Step-by-step explanation:

(5-8x)

-----------------

sqrt(-8x+5)

We need to rationalize the denominator

(5-8x) sqrt(-8x+5)

----------------- * ---------------

sqrt(-8x-5) sqrt(-8x+5)

(5-8x) sqrt(-8x+5)

----------------- * ---------------

(-8x+5)

The first term cancels

sqrt(-8x+5)

8 0

2 years ago

Read 2 more answers

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$

And the standard deviation of the distribution of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74$

Thus, the distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b)

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the value of $P(\bar X$ is 0.7642.

(c)

Compute the value of $P(\bar X\geq 69.1)$ as follows:

Apply continuity correction as follows:

$P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)$

$=P(\bar X>69.6)$

$=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})$

$=P(Z>0.34)\\=1-P(Z$

Thus, the value of $P(\bar X\geq 69.1)$ is 0.3670.

7 0

2 years ago

Ann started reading at 4:00 p.m. And finished at 4:20 p.m. Through what fraction of a circle did the minute hand turn?

Basile [38]

20/12???....................

8 0

2 years ago

Read 2 more answers

A)What is the greatest common factor (GCF) for 18 and 66?<br>Show your work.

zaharov [31]

Answer:

Step-by-step explanation:

18: 1, 2, 3, 6, 9, 18

66:, 1,2,3,6,11,22,33,66

the GCF is 6

7 0

2 years ago

Robin is flying a kite. She ties the 50 foot kite string to the ground. If the kite is

krok68 [10]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>given </u><u>in </u><u>the </u><u>question </u><u>that</u><u>, </u><u> </u><u>Robin </u><u>is </u><u>flying </u><u>a </u><u>kite</u><u>. </u>
<u>She </u><u>ties </u><u>the </u><u>5</u><u>0</u><u> </u><u>foot </u><u>kite </u><u>string </u><u>to </u><u>the </u><u>ground </u><u>.</u>
<u>The</u><u> </u><u>kite </u><u>is </u><u>flying </u><u>at </u><u>4</u><u>0</u><u> </u><u>feet </u><u>high </u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>measure </u><u>of </u><u>the </u><u>angle </u><u>the </u><u>string </u><u>forms </u><u>with </u><u>the </u><u>group </u><u>that </u><u>is </u><u>angle </u><u>of </u><u>elevation</u><u>. </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>According </u><u>to </u><u>the </u><u>given</u><u> </u><u>question</u><u>, </u>

Hypotenuse AC ( Distance of string from the ground) = 50 ft.
Perpendicular height AB ( Distance of the kite from the ground) = 40 ft.

<h3><u>Therefore</u><u>, </u></h3>

<u>By </u><u>using </u><u>trigonometric </u><u>ratios</u><u>,</u><u> </u>

{ $\bold{\pink{ Sin Φ = }}{\bold{\pink{\dfrac{Perpendicular}{Hypotenuse }}}}$

$\bold{\red{ Cos Φ = }}{\bold{\red{\dfrac{Base}{Hypotenuse }}}}$

$\bold{\purple{ Sin Φ = }}{\bold{\purple{\dfrac{Perpendicular}{Base }}}}$ }

<u>The </u><u>Angle </u><u>of </u><u>elevation </u><u>will </u><u>be </u>

<u>[</u><u> </u><u>The </u><u>angle </u><u>that </u><u>is </u><u>formed </u><u>between </u><u>the </u><u>line </u><u>of </u><u>sight </u><u>and </u><u>base </u><u>of </u><u>the </u><u>triangle </u><u>is </u><u>called </u><u>angle </u><u>of </u><u>elevation </u><u>]</u>

$\bold{\pink{Sin Φ = }}{\bold{\pink{\dfrac{AB}{AC }}}}$

$\sf{ Sin Φ = }{\sf{\dfrac{40}{50 }}}$

$\sf{ Sin Φ = }{\sf{\dfrac{4}{5}}}$

$\sf{ Sin Φ = 0.8 }$

$\bold{\green{ Φ = 45.83° }}$

Hence, The measure of the angle the string forms with the ground is 45.83° .

7 0

1 year ago