Answer: Option (b) is the correct answer.
Explanation:
The elements which have excess or deficiency of electrons will react readily.
Atomic number of Mn is 25 and electronic configuration of is [Ar]. This configuration is stable.
Atomic number of Cr is 24 and electronic configuration of is [Ar]. This configuration is not stable.
Atomic number of Fe is 26 and electronic configuration of is [Ar]. This configuration is stable.
Atomic number of Cu is 29 and electronic configuration of is [Ar]. This configuration is not stable.
Atomic number of Al is 13 and electronic configuration of Al is . This configuration is not stable.
Atomic number of Ba is 56 and electronic configuration of is [Kr]. This configuration is stable.
Atomic number of Mg is 12 and electronic configuration of is . This configuration is stable.
Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]. This configuration is stable.
Thus, we can conclude that out of the given options, only Fe and reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.
Answer:
Matter is anything that mass and can occupy space.
Atoms are the smallest particles that takes part in a chemical reaction.
A molecule is a that can exist on its own
We can see from the details below that, the value of the solution's molality is 1.14 mol/Kg.
<h3>What is solubility?</h3>
The term solubility has to do with the quantity of solute that is able to dissolve in a given quantity of solvent. We have the solubility of the sodium hydrogen carbonate in water at 20 degrees as 9.6 g/100 g h2o.
Number of moles of sodium hydrogen carbonate = 9.6 g/84 g/mol = 0.114 moles
Number of moles water = 100 g /18 g/mol = 5.55 moles
Mole fraction of sodium hydrogen carbonate is obtainable by the use of the relation;
0.114 moles/0.114 moles + 5.55 moles
= 0.02
Molality of the solution = 0.114 moles/0.1 Kg = 1.14 mol/Kg
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Answer:
10.88 g
Explanation:
We have:
[CH₃COOH] = 0.10 M
pH = 5.25
Ka = 1.80x10⁻⁵
V = 250.0 mL = 0.250 L
The pH of the buffer solution is:
(1)
By solving equation (1) for [CH₃COONa*3H₂O] we have:
Hence, the mass of the sodium acetate tri-hydrate is:
Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.
I hope it helps you!