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2 years ago

Calculate the how many sodium atoms must react completely to give 33,6 dm³ hydro-

Chemistry

1 answer:

lions [1.4K]2 years ago

8 0

To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

<h3>What is Mole concept ?</h3>

A mole is a unit of measurement used to measure the amount of any fundamental entity (atoms, molecules, ions) present in the substance.

As according to the given equation, 2 moles (ie 12.04 x 10²³ atoms) of Na-atoms produces 1 mole (22.4 ltr) of H₂-gas.

Hence, to produce 33.6 ltr (equivalent to 33.6 dm³) of H₂-gas produced by ;

= 12.04 x 10²³ atoms of Na / 22.4 ltr of H₂-gas x 33.6 ltr

= 18.06 x 10²³ atoms of Na

Hence, To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

Learn more about Mole concept here ;

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Answer:

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3 years ago

Calculate the ph of a buffer that is 0.225 m hc2h3o2 and 0.162 m kc2h3o2. the ka for hc2h3o2 is 1.8 Ã 10-5. 4.60 9.26 4.74 4.89

Stella [2.4K]

Answer:

The pH of the buffer solution is 4.60.

Explanation:

Concentration of acid = $[HC_2H_3O_2]=0.225 M$

Concentration of salt = $[KC_2H_3O_2]=0.162 M$

Dissociation constant = $K_a=1.8 \times 10^{-5}$

The pH of the buffer can be determined by Henderson-Hasselbalch equation:

$pH=pK_a+\log\frac{[salt]}{[acid]}$

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The pH of the buffer solution is 4.60.

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3 years ago

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How was Bohr's atomic model different from those of previous scientists?

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Answer:

Bohr placed the electrons in distinct energy levels. Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantized orbits. Also, rutherfords was just a hypothesis while Bhor took the time to make his an experiment

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3 years ago

In a zero order reaction, it takes 342 seconds for 75% of a hypothetical reactant to decompose. Determine the half-life t_{1/2}

stiv31 [10]

Answer:

228 s

Explanation:

In a zero order reaction, the formula for the half life is given as;

t1/2 = [A]o / 2k

To obtain the rate constant k, we have to use;

[A] = [A]o - kt

kt = [A]o - [A]

From the question;

it takes 342 seconds for 75% of a hypothetical reactant to decompose.

We have;

t = 324

[A] = 25

[A]o = 100

Upon solving for k we have;

kt = [A]o - [A]

k = ( [A]o - [A] ) / t

k = (100 - 25 ) / 342

k = 75 / 342 = 0.2193

Solving for t1/2;

t1/2 = [A]o / 2k

t1/2 = 100 / 2(0.2193)

t1/2 = 100 / 0.4386 = 228 s

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3 years ago