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2 years ago

Calculate the how many sodium atoms must react completely to give 33,6 dm³ hydro-

Chemistry

1 answer:

lions [1.4K]2 years ago

8 0

To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

<h3>What is Mole concept ?</h3>

A mole is a unit of measurement used to measure the amount of any fundamental entity (atoms, molecules, ions) present in the substance.

As according to the given equation, 2 moles (ie 12.04 x 10²³ atoms) of Na-atoms produces 1 mole (22.4 ltr) of H₂-gas.

Hence, to produce 33.6 ltr (equivalent to 33.6 dm³) of H₂-gas produced by ;

= 12.04 x 10²³ atoms of Na / 22.4 ltr of H₂-gas x 33.6 ltr

= 18.06 x 10²³ atoms of Na

Hence, To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

Learn more about Mole concept here ;

brainly.com/question/20483253

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Answer:

$Molec_{\ H_{tot}}=1.206x10^{25}molec$

Explanation:

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In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

$molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH} =6.03x10^{22}molec$

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$molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH} =1.20x10^{25}molec$

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