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kirill [66]
3 years ago
10

Solid magnesium hydroxide decomposes into solid magnesium oxide and gaseous water . Write a balanced chemical equation for this

reaction
Chemistry
2 answers:
Mashcka [7]3 years ago
4 0

Answer: Mg(OH)_2(s)\rioghtarrow MgO(s)+H_2O(g)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

The balanced equation for decomposition of solid magnesium hydroxide decomposes into solid magnesium oxide and gaseous water is:

Mg(OH)_2(s)\rioghtarrow MgO(s)+H_2O(g)

(s) represents solid state and (g) represents gaseous state.

konstantin123 [22]3 years ago
3 0
Equation: MgOH2 (s) --> MgO (s) + H2O (g)

And it's already balanced.

I had chemistry this semester too.
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How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?
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Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound  = 1.43g

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Number of particles of sodium = ?

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To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

          Mass of sodium  = \frac{molar mass of Na}{molar mass of compound} x mass of sample

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3 years ago
Calculate the number of moles of solute present in 185.0 mL of a 1.50 mol/L solution of HCl.
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0.278 mol HCl

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185.0 / 1000 = 0.185 L

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0.185 L * 1.50 mol/L = 0.278 mol HCl

Thus the answer is 0.278 mol HCl.

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