It condenses very long strings of numbers while retaining the general accuracy of the figure.
Answer:
Its B
Explanation: I did the test passed btw
Answer:
3.74 x 10²² particles
Explanation:
Given parameters:
Mass of compound = 1.43g
Molar mass of compound = 23g
Unknown:
Number of particles of sodium = ?
Solution:
To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;
Mass of sodium = 
= 
= 1.43g
Now find the number of moles of this amount of Na in the sample;
Number of moles =
=
= 0.062mole
Now;
1 mole of substance = 6.02 x 10²³ particles
0.062 mole of substance = 0.062 x 6.02 x 10²³ particles
= 3.74 x 10²² particles
Answer:
0.278 mol HCl
Explanation:
We currently have 185.0 mL of a 1.50 mol/L solution of HCl. We want to find the number of moles there are.
Based on the given information, our volume is 185.0 mL and our molarity is 1.50. Because molarity is defined as moles / Litre, we can easily find the moles given volume by multiplying molarity by volume.
First, though, we must convert millilitres to litres. There are 1000 mL in 1 L, so divide 185.0 by 1000:
185.0 / 1000 = 0.185 L
Now, multiply 0.185 by 1.50:
0.185 L * 1.50 mol/L = 0.278 mol HCl
Thus the answer is 0.278 mol HCl.
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