Answer:
There will be one Al3+ ion.
There will be 3 NO3- ions
Explanation:
Dissociation equation:
Al(NO₃)₃ → Al³⁺ + 3NO₃¹⁻
When aluminium nitrate dissociate it produces one silver ion (Al³⁺) and three (NO₃¹⁻) ions.
Properties of Al(NO₃)₃:
It is inorganic compound having molecular mass 169.87 g/mol.
It is white odor less compound.
Its density is 4.35 g/mL.
Its melting and boiling points are 120°C and 440°C.
It is soluble in water.
It is sued to treat infections.
It is used in the photographic films.
It s toxic and must be handled with great care.
Answer:
The answer should be 1000 kg / m3
Answer:
Cu+(aq)--->Cu2+(aq) + e- : oxidation
reason: there is loss of electrons.
I2(s) + 2e--->2I-(aq) : reduction
reason: There is reduction of electrons.
<h3>
Answer:</h3>
2670 g Hg
<h3>General Formulas and Concepts:
</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>Explanation:
</h3>
<u>Step 1: Define</u>
8.02 × 10²⁴ atoms Hg
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Hg - 200.59 g/mol
<u>Step 3: Convert</u>
- Set up:

- Divide/Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2671.42 g Hg ≈ 2670 g Hg
Answer:
Density rectangular block = 7.47 (Approx) gm/cm³
Explanation:
Given:
Length = 8.335 cm
Width = 1.02 cm
Height = 0.982 cm
Mass = 62.3538 gm
Find:
Density rectangular block
Computation:
Volume of block = lbh
Volume of block = (8.335)(1.02)(0.982)
Volume of block = 8.3486 cm³
Density = Mass / Volume
Density rectangular block = 62.3538 / 8.3486
Density rectangular block = 7.47 (Approx) gm/cm³