Molarity of solution is expressed as,
Molarity =
Molecular weight of KCl = 74.55 g/mol
For preparing 1 mol of KCl solution (1 liter), 74.44 g KCl must be dissolved in 1 liter of water.
Following glasswares are required for preparing the solution.
1) Watch Glass (for weight the KCl)
2) Beaker (for preparing the solution)
3) Stirrer (For dissolving KCl in water)
4) Standard measuring flask (To ensure final volume of solution is 1 liter)
Answer:
Tara is making a scrapbook using 24 photos and 8 newspaper clippings. She wants to put the same number of photos and clippings on each page. What is the greatest number of scrapbook pages Tara can make?
Explanation:
Tara is making a scrapbook using 24 photos and 8 newspaper clippings. She wants to put the same number of photos and clippings on each page. What is the greatest number of scrapbook pages Tara can make?
439.3 g CO2
Explanation:
First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:
3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)
= 9.981 mol CO2
Use the molar mass of CO2 to determine the # of grams of CO2:
9.981 mol CO2 x (44.01 g CO2/1 mol CO2)
= 439.3 g CO2
Sodium carbonate is used to neutralised sulfuric acid, H₂SO₄. Sodium carbonate is the salt of stron base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:
Na₂CO₃ + H₂SO₄→ Na₂SO₄ + H₂CO₃
From balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of H₂SO₄. Molar mass of Na₂CO₃= 106 g/mol=0.106 kg/mol and molar mass of H₂SO₄= 98 g/mol=0.098 kg/mol.
To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, to neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is=
kg= 5.451 X 10³ kg.
