We are given the
perimeter of isosceles trapezoid = 28 in
ratio of length of bases = 5:3
We are to find the lengths of sides of the trapezoid and the diagonal that bisects the angle at the base with a longer length
The formula for the perimeter of an isosceles trapezoid is
P = (1/2) (b1 + b2) h
We are given the ratio
b2/ b1 = 5 /3
b2 = 5/3 b1
Substituting
28 = (1/2) (5/3 b1) h
The height of the trapezoid is expressed in terms of b1
For the diagonal
d² = h² + [(b2 - b1) + (b2 - b1)/2]²
Express h and b2 in terms of b1 and diagonal can be expressed in terms of b1
Answer:
64
Step-by-step explanation:
because each ticket cost 8 dollars you would then multiply it by 8
Answer:
144 inches.
Step-by-step explanation:
One foot = 12 inches
One square foot = 144 inches.
Given a triangle with a base of 15.22 km and a height of 13.91 km. We can find the area of the triangle using the formula below.


Answer: The area of the triangle is
45 adult tickets and 80 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 6
Cost of 1 children ticket = $ 3.50
<em><u>They sold a total of 125 tickets</u></em>
Therefore,
a + c = 125
c = 125 - a --------- eqn 1
<em><u>They made a total of $550. Therefore, frame a equation as:</u></em>
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = 550

6a + 3.50c = 550 ----------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
6a + 3.50(125 - a) = 550
6a + 437.5 - 3.50a = 550
2.5a = 112.5
<h3>a = 45</h3>
<em><u>Substitute a = 45 in eqn 1</u></em>
c = 125 - 45
<h3>c = 80</h3>
Thus 45 adult tickets and 80 children tickets were sold