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guapka [62]
2 years ago
5

If LO ≅LM and OP ≅ PM , then a correct conclusion would be:

Mathematics
1 answer:
Brrunno [24]2 years ago
5 0

Answer:

Step-by-step explanation:

None of these Choices are correct..

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Help plz i really appreciate it ​
yuradex [85]

Answer:

Variant A

Step-by-step explanation:

1)y= - 3x+1

2)y+5= - 3(x-2)

y+5= - 3x+6

y= -3x+1

They are equal

6 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
2 years ago
Need help with volume !!
Scorpion4ik [409]

Answer:

16m

Step-by-step explanation:

4 x 2 = 8
8 x 2 = 16

5 0
2 years ago
Will mark BRAINLIESTT
bogdanovich [222]

Answer:

2.5

Step-by-step explanation:

16-13.50

6 0
2 years ago
Read 2 more answers
A liquid at temperature 7575F is placed in an oven at temperature 450450. The temperature of the liquid increases at a rate 77 t
hichkok12 [17]

Answer: \dfrac{dT(t)}{dt}=77\times (450-T)

Step-by-step explanation:

Given

The temperature of the liquid is 75^{\circ}F placed in an oven with temperature of 450^{\circ}F.

Initially difference in temperature of the two

\Delta T=450-75\\\Rightarrow \Delta T=375^{\circ}F

According to the question

\Rightarrow \dfrac{dT(t)}{dt}=77\cdot \Delta T\\\\\Rightarrow \dfrac{dT(t)}{dt}=77\times (450-T)\quad [\text{T=75}^{\circ}F\ \text{at t=0}]

5 0
2 years ago
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