V-16=-32I need help with the math worksheet how to solve the question

Mathematics

1 answer:

sergeinik [125]3 years ago

8 0

You solve an equation like this by adding the opposite of the constant to both sides of the equation.

... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b

... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0

... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V

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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

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Use the zero product property to find the solutions to the equation (x 2) (x 3) = 12.

oee [108]

The solution of the given equation is -6 and 1.

<h3>What is Quadratic Equation?</h3>

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

Here, given equation:

(x+2)(x+3) = 12

x(x+3)+2(x+3) = 12

x² + 3x + 2x + 6 = 12

x² + 5x + 6 - 12 = 0

x² + 5x - 6 = 0

x² + 6x - x - 6 = 0

x(x+6) -1(x+6) = 0

(x+6)(x-1) = 0

Now, x + 6 = 0 or x - 1 = 0

x = -6 or x = 1

Thus, the solution of the given equation is -6 and 1.