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sleet_krkn [62]
3 years ago
14

V-16=-32I need help with the math worksheet how to solve the question

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

You solve an equation like this by adding the opposite of the constant to both sides of the equation.

... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b

... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0

... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V

_____

<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

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Can you help me and show work 2 <br> Thank you
enyata [817]

Answer:

sure it's 3 2/3

Step-by-step explanation:

the yards are 50 inches so it is going to be

6 0
3 years ago
What is the square root of 378904
zvonat [6]

Simplify the following:

sqrt(378904)

sqrt(378904) = sqrt(8×47363) = sqrt(2^3×47363):

sqrt(2^3 47363)

sqrt(2^3 47363) = sqrt(2^3) sqrt(47363) = 2 sqrt(2) sqrt(47363):

2 sqrt(2) sqrt(47363)

sqrt(2) sqrt(47363) = sqrt(2×47363):

2 sqrt(2×47363)

2×47363 = 94726:

Answer:  2 sqrt(94726)

6 0
3 years ago
Two pieces of equipment were purchased for a total of $4000. If one piece cost $850 more than
ruslelena [56]

The price of less expensive equipment is $1575.

Step-by-step explanation:

Let,

Price of one equipment = x

Price of other equipment = y

According to given statement;

x+y=4000   Eqn 1

x = y+850    Eqn 2

Putting Eqn 2 in Eqn 1

(y+850)+y=4000\\y+850+y=4000\\2y=4000-850\\2y=3150

Dividing both sides by 2;

\frac{2y}{2}=\frac{3150}{2}\\y=1575

Putting y=1575 in Eqn 2;

x=1575+850\\x=2425

The price of less expensive equipment is $1575.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/11343416
  • brainly.com/question/11416224

#LearnwithBrainly

3 0
3 years ago
A box holds 42 pieces of red construction paper and 18 pieces of blue construction paper. A piece of paper is pulled out of the
dimulka [17.4K]
<u>First problem :</u>
probability to draw a red paper : 42/(42+18)=7/10

In 110 tries one can thus expect to draw 7/10*110=77 red papers

<u>Second problem :</u>
Since for 150 trials (which will give the least error) we have got 135 yellow balls, we can expect twice as much in 300=150*2 trials, which makes 270 yellow balls.
3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
saul85 [17]

Answer:

\sqrt{0.02}

Step-by-step explanation:

Let's first get the square root of 0.02...

≅ 0.1414

Let's convert that to a percentage...

14.14%, which is less than 18%, so it checks out in that sense...

Now, let's convert 0.1414 to a fraction...

\frac{707}{5000}, which is greater than  \frac{1}{8}  (You can check this by multiplying \frac{1}{8} by \frac{625}{625})

Therefore, \sqrt{0.02} makes the inequality true.

6 0
3 years ago
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