The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
    (x+2)(x+3) = 12
  x(x+3)+2(x+3) = 12
  x² + 3x + 2x + 6 = 12
  x² + 5x + 6 - 12 = 0
  x² + 5x - 6 = 0
  x² + 6x - x - 6 = 0
  x(x+6) -1(x+6) = 0
  (x+6)(x-1) = 0
Now, x + 6 = 0      or      x - 1 = 0
          x = -6           or      x = 1
Thus, the solution of the given equation is -6 and 1.
Learn more about Quadratic Equation from:
brainly.com/question/17177510
#SPJ1
 
        
             
        
        
        
Answer:
The solution is given below:
Step-by-step explanation:

As we know the value of k and r so the equation will be 





 
        
                    
             
        
        
        
Answer:
The answer is D. 2 
Step-by-step explanation:
exponential form
exponents equal
move constant to the right
subtract the number
divide both sides by 2
 
        
             
        
        
        
Answer:

Step-by-step explanation:
Given

Required
Gaps: -2( )-2( )=8
<em>Fill in in the gaps</em>
The are numerous solutions to this.
One of them is:
Assume y = 0.
So, we have:



Divide through by -2


Fill in the gaps with these values of x and y respectively:
Hence; one solution is: 
 
        
             
        
        
        
Answer is -44+x^2 . First you need to evaluate the equation and get 5+x^2-49 then u calculate it and your final answer is -44+x^2