Question

What is the equation of a line with points (16,-4) and (-32-10) Oy - 4= 1 (x - 16) Oy+4= 1 (x – 16) Oy - 10 = 3 (x – 32) O y + 10 = 1 (x + 32)​

Answer 1

Answer:

• D. y + 10 = 1/8* (x + 32)

Step-by-step explanation:

Use the given points to work out the equation of the line.

Find the slope:

• m = (- 10 - (-4)) / (- 32 - 16) = - 6 / - 48 = 1/8

Use (-32, - 10) and point- slope form:

• y - (- 10) = 1/8*(x - (-32))
• y + 10 = 1/8* (x + 32)

Correct choice is D

Answer 2

Points

• (16,-4)
• (-32,-10)

Equation of line in two points form

$\\ \sf\longmapsto y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$\\ \sf\longmapsto y+10=\dfrac{-10+4}{-32-16}(x+32)$

$\\ \sf\longmapsto y+10=\dfrac{-6}{-48}(x+32)$

$\\ \sf\longmapsto y+10=\dfrac{1}{8}(x+32)$

Option D