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yawa3891 [41]
3 years ago
7

sarah owes 22.40 for her text messaging in the month of march. If her texting message plan costs 14 dollars for the first 250 me

ssages and .5 cent for each additional messages how many text messages did she send that month?
Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
0.5 times 16 equals 8 so that’s 276 messages 0.5 to get 40 cents is 8 more so 276 messages in all I hope I did this right
Valentin [98]3 years ago
4 0

The answer is 267.

If we wanted to represent this scenario as an equation, it would be 22.40-14+.5x (x being the amount of texts after 250). We are using PEMDAS, but because the variable is unknown, we skip multiplication and just go left to right. 22.40 - 14 = 8.40. With 8.40, we now know how much it costed AFTER 250 messages (how much she owes after $14). If we want to find how many PER 50 cents, we have to DIVIDE (reverse of multiplication). 8.4 / .5 = 16.80. Because you can't send .8 of a text message, you round to get 17. 250 + 17 = 267 (messages sent that month).

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Differentiate the following functions (x^3+1)(x-2)÷x^2​
Masja [62]

Given:

The given function is:

\dfrac{(x^3+1)(x-2)}{x^2}

To find:

The differentiation of the given function.

Solution:

Consider the given function,

y=\dfrac{(x^3+1)(x-2)}{x^2}

It can be written as:

y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}

y=\dfrac{x^4-2x^3+x-2}{x^2}

y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}

y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}

Differentiate with respect to x.

y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})

y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})

y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}  

Therefore, the differentiation of the given function is 2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}.

8 0
3 years ago
Solve 2x2 – 6x + 10 = 0 by completing the square.
astraxan [27]

Answer: x = 6.32 or -0.32

Step-by-step explanation:

2x² - 6x + 10  = 0

No we divide the expression by 2 to make the coefficient of x² equals 1

We now have

x² - 3x + 5     = 0

Now we remove 5 to the other side of the equation

x² - 3x          = -5

we add to both side square of  half the coefficient of x which is 3

x² - 3x + ( ⁻³/₂)²  = -5 + (⁻³/₂)²

(x  -  ³/₂)²           = -5 + ⁹/₄

Resolve into fraction

(x  - ³/₂)²             = ⁻¹¹/4

Take the roots of the equation

 x - ³/₂               = √¹¹/₄

 x - ³/₂               = √11/₂

x                       = ³/₂ ± 3.32/₂

                         = 3+ 3.32 or 3 - 3.32

                         =  6.32 or - 0.32

4 0
3 years ago
Can anyone pls solve this.
OLga [1]

Answer:

3) \frac{(25)^{3/2} * (243)^{3/5}}{(16)^{5/4}*(8)^{4/3}}

=> \frac{(5^2)^{3/2}*(3^5)^{3/5}}{(2^4)^{5/4}*(2^3)^{4/3}}

=> \frac{5^3*5^3}{2^5*2^4}

=> \frac{5^6}{2^9}

4) \frac{3-2\sqrt{2} }{3+2\sqrt{2} }

Multiplying and dividing by conjugate 3-2\sqrt{2}

=> \frac{(3-2\sqrt{2})(3-2\sqrt{2}) }{(3+2\sqrt{2})(3-2\sqrt{2})}

=> \frac{9-6\sqrt{2}-6\sqrt{2} +8 }{9-8}

=> \frac{17-12\sqrt{2} }{1}

=> 17-12\sqrt{2}

Comparing it with a+b\sqrt{2}, we get

a = 17, b = -12

7 0
3 years ago
(25 points) PLEASE HELP! Gotta get this done before my mom comes home
Artemon [7]
Hey, the only one I could figure out was no. 2 and 3. Sorry.

Answer:
2. D) Red roses: 126; pink roses: 162
3. C) S+H=46 H=S-2

I hope you found this helpful :)
7 0
4 years ago
Will V − E + F always equal 2?
SVEN [57.7K]

The expression V − E + F is an illustration of the Euler's formula.

The expression V − E + F is always 2

<h3>How to determine the true statement?</h3>

The equation is given as:

V - E + F = 2

Where:

  • V represents the vertices
  • E represents the edges
  • F represents the faces

According to the Euler's formula, the relationship between V, E and F is:

V + F = 2 + E

Subtract E from both sides

V - E + F = 2

Hence, the expression V − E + F is always 2

Read more about Euler's formula at:

brainly.com/question/12274716

7 0
2 years ago
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