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sergeinik [125]
3 years ago
12

If you prepare 525 mL of a .650M MgCl2 solution, how many grams of solute would you need?

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

Explanation:

525ml of 0.6550M MgCl₂ => 0.525L x 0.650M = 0.3413mole MgCl₂

0.3413mole MgCl₂ = 0.3413mole x 94 g/mole = 32.1g MgCl₂

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