All categories

2 years ago

25 - 5 x 2^2 + 1 will give brainliest!

Mathematics

2 answers:

ivolga24 [154]2 years ago

8 0

Answer:

$25\:-\:5\:\cdot \:2^2\:+\:1 = 6$

Step-by-step explanation:

$25-5\cdot \:2^2+1$

Calculate exponents $2^2 : 4$

$=25-5\cdot \:4+1$

Multiply and divide (left to right) $5\cdot \:4 : 20$

$=25-20+1$

Add and subtract (left to right) $25-20+1 : 6$

$= 6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

GREYUIT [131]2 years ago

5 0

Answer:

-20x+26

Step-by-step explanation:

$25-5x\cdot \:2^2+1\\-2^2\cdot \:5x+26\\-20x+26$

You might be interested in

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0

3 years ago

Janet Fog's uncle, Pete Moore, promised her a gift of $30,000 upon her graduation from law school or $1500 every quarter for the

LenaWriter [7]

First calculate the future value of the annuity
The formula to find the future value of an annuity ordinary is
Fv=pmt [((1+r/k)^(kn)-1)÷(r/k)]
Fv future value?
PMT quarterly payment 1500
R interest rate 0.12
K compounded quarterly 4
N time 4 years
Fv=1,500×(((1+0.12÷4)^(4×4)
−1)÷(0.12÷4))
=30,235.32

Now compare the amount of the annuity with amount of the gift
30,235.32−30,000=235.32
So as you can see the amount of the annuity is better than the amount of the gift by 235.32

Second offer is better

Hope it helps!

5 0

3 years ago

Please help. Algebra.

ladessa [460]

The answer is 1 bc the solution is (1,-3)

7 0

3 years ago

Pat is making 5 stools with circular seats that are each 12 inches in diameter. She wants to paint the tops of all the stools br

vivado [14]

Start by finding the area of one of the stools with this formula:
A=(3.14)(12)(12)
Then multiply that answer by five, since there are 5 stools.
Hope this helps :) good luck

6 0

2 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$

Then, the margin of error is:

$MOE=z \cdot s_{pm-pw}=1.645\cdot 0.029=0.0477$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.212-0.0477=-0.260\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.212+0.0477=-0.165$

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

6 0

3 years ago