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Marianna [84]
2 years ago
14

| 19 − 20x | − |20 − 19x |− |x − 10|, if x > 100

Mathematics
1 answer:
denpristay [2]2 years ago
4 0

Answer:

11

Step-by-step explanation:

since x>100, then 19-20x and 20-19x would obviously be negative and x-10 would be positive.

Therefore we have (20x-19)-(19x-20)-(x-10) = 20x-19-19x+20-x+10 = 11

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Answer:

13 + 5 + 37

Step-by-step explanation:

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Let f(x) = -2x + 4 and g(x) = 5x - 7. Find f(x) - g(x).
balandron [24]

Answer:

If you are just looking for a simplified answer then the answer is -7x - 3.

4 0
3 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

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3 years ago
WILL MARK BRAINLIEST<br><br> Please help solve problems with common tangents.
kirza4 [7]

Answer:

not sure, sorry : p

Step-by-step explanation:

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2 years ago
Amy ran 2/3 of a marathon. Beth ran 5/6 of a marathon. Who ran farther ? How much farther?
Ymorist [56]
2/3 is equal to 4/6. 

So, Beth ran further by 1/6 of the marathon
3 0
3 years ago
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