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Answer:
The required formula is:
Step-by-step explanation:
The total number of squares of the the first term = 4
The total number of squares of the the second term = 7
The total number of squares of the the third term = 10
so,
Finding the common difference d
As the common difference 'd' is same, it means the sequence is in arithmetic.
So
If the initial term of an arithmetic progression is and the common difference of successive members is d, then the nth term of the sequence
is given by:
Therefore, the required formula is:
Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:
Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.