Please help with both problems

Please help I really need your help

Amanda [17]

Answer:

1. $1200 \ kg/m^3$

2.

a)

35 cm = 0.35 meters

11 dm = 1.1 meters

15 mm = 0.015 meters

b)

Volume = 0.005775 cubic meters

Mass = 15.5925 kilograms

Step-by-step explanation:

1.

We know

Density = Mass/Volume

Given

Mass = 90 kg

Volume = 0.075 cubic meters

The SI unit for density is kilograms per cubic meters. Our dimensions are just that, so we just need to plug in the numbers into the formula and get our answer. Shown below:

Density = $\frac{90}{0.075}=1200 \ kg/m^3$

The Density of asphalt block = $1200 \ kg/m^3$

2.

a)

We need to express 35cm, 11dm, and 15mm in meters

We know

100 cm = 1 meters, so

35 cm = 35/100 = 0.35 meters

We know 1 dm = 0.1 meters, so

11 dm * 0.1 = 1.1 meters

We know, 1mm = 0.001 meters, so

15 mm * 0.001 = 0.015 meters

b)

Volume of the Slab is length * width * height, in meters, that would be:

Volume = 0.35 * 1.1 * 0.015 = 0.005775 cubic meters

THe mass would be found by the formula:

Density = Mass/Volume

2700 = Mass/0.005775

Mass = 0.005775 * 2700 = 15.5925 kilograms

5 0

3 years ago

With bases V1, V2 , V3 andw1, w2 , W3, suppose T(v1) = w2 and T(v2) = T(v3) = w1 + w3 . T is a linear transformation. Find the m

Roman55 [17]

Answer:

See picture and explanation below.

Step-by-step explanation:

With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.

A is defined as $T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)]$ denotes the vector of coordinates of $T(v_i)$ respect to the basis (we can apply this definition because forms a basis for the domain of T).

The vector of coordinates can be computed in the following way: if $T(v_i)=a_1w_1+a_2w_2+a_3w_3$ then $[T(v_i)]=(a_1,a_2,a_3)^t$ .

Note that we have all the required information: $T(v_1)=0w_1+1\cdot w_2+0w_3$ then $[T(v_1)]=(0,1,0)^t$

$T(v_2)=T(v_3)=1\cdot w_1+0w_2+0w_3$ hence $[T(v_2)]=[T(v_3)]=(1,0,0)^t$

The matrix A is on the picture attached, with the multiplication A(1,1,1).

Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:

$T(v_1+v_2+v_3)=T(v_1)+T(v_2)+T(v_3)=w_2+w_1+w_1=w_2+2w_1$

In this last case, we can either use the linearity of T or multiply by A.

4 0

3 years ago

Problems on a Test

patriot [66]

G = 4n is the correct equation to use. Eg 10 x 4 = 40, 18 x 4 = 72 and 21 x 4 = 84

6 0

3 years ago

Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )

Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

$(\frac{a + b}{b} - \frac{a}{a + b}) \div ( \frac{a + b}{a} - \frac{b}{a + b})$

$(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})$

$\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}$

$\implies \frac{a}{b}$

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0

2 years ago

Read 2 more answers

Find the distance between the points given.<br><br> (-3, 2) and (9, -3)

g100num [7]

The distance will be given by the equation;
D= $\sqrt{( x_{1} - x_{2} )^{2} +( y_{1} - y_{2} )^{2} }$
D= $\sqrt{ (-3-9)^{2}+( 2--3)^{2} }$
D= $\sqrt{ (-12)^{2} + (5)^{2} }$
D= $\sqrt{169}$
D=13 units

8 0

3 years ago