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lawyer [7]
2 years ago
14

Please help with both problems

Mathematics
1 answer:
erica [24]2 years ago
8 0
Okay so i cant figure out the first one, but the second one looks like -7:3
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john started homework at 7:00 pm he finish at 3:00 then he checked double the amount last time how much time did he spend
Scilla [17]
K, so am assuming of th next day

from 7pm to 12 midnight is 5 hours
from 12 midnight so 3am is 3 hours
3+5=8

8 hours total

checked double the amoutn last time
he spent 16 hours last time?
8 0
3 years ago
The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o
IgorLugansk [536]

Answer:

y=0.2x+29

Step-by-step explanation:

Given that:

y is the total monthly of the A Fee and Fee plan.

x is the number of monthly minutes used.

  • If a customer uses 290 minutes, the monthly cost will be $87, we have the pair (290, 87)
  • If the customer uses 980 minutes, the monthly cost will be $225, this is the coordinate pair (980, 225).

We want to obtain an equation in the form: y=mx+b

First, let us determine the slope, m

Given points (290, 87) and (980, 225):

<u>Slope</u>

m=\dfrac{225-87}{980-290} =\dfrac{138}{690}=0.2

Next, we determine the y-intercept, b.

Substituting the pair (290, 87) and m=0.2 in y=mx+b, we obtain

87=0.2(290)+b

b=87-0.2(290)=29

Therefore, our equation in the form y=mx+b is:

y=0.2x+29

8 0
2 years ago
Write the equation of the line that passes through (5.-9) and (2.5).
Kipish [7]

Answer:

y = -14/3x + 43/3

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-9) / 2 - 5

14 / -3

- 14/3

y = -14/3x + b

5 = -14/3(2) + b

5 = -28/3 + b

43/3 = b

y = -14/3x + 43/3

4 0
3 years ago
Share £180 in the 4:5
marissa [1.9K]
4 + 5 = 9
£180 / 9 = £20

£20 x 4 = £80
£20 x 5 =£100

Answer:
£80 : £100

hope it helped :)
4 0
3 years ago
) How is the Domain for the function f(x) = (x restricted?​
konstantin123 [22]
The function f(x) = (x)? If that is the function, then there is no retriction on the Domain?
6 0
2 years ago
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