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Helga [31]
3 years ago
14

What is the potential difference in charge called

Physics
1 answer:
Svetach [21]3 years ago
6 0

Answer: Potential difference

Explanation:l Let me explain

According to my understanding potential difference is always between two points. It is work done in moving a charge from one point to another

V=W/q

This PD of a charge would be work done in moving it from one place to another.

Hope this helps

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The speed limit on some interstate highways is roughly 80 km/h. What is this in meters per second? How many miles per hour is th
sergey [27]

Answer:

1) Speed in m/s equals 22.22 m/s.

2) Speed in miles per hour equals 49.712 mph.

Explanation:

Since we know that in 1 kilometer there are 1000 meters and in 1 hour there are 3600 seconds hence we can write

80km/h=\frac{80\times 1000m}{3600s}=22.22m/s

Now we know that 1 mile equals 1.609 kilometer  hence we conclude that 1 kilometer equals \frac{1}{1.609}=0.6214mile

Hence

80km/h=\frac{80\times 0.6214miles}{1h}=49.712mph

3 0
4 years ago
A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels.
shutvik [7]

Answer:

a = 6.53 m/s^2

v = 11.5689 m/s

Explanation:

Given data:

engine power is 217 hp

70 % power reached to wheel

total mass ( car + driver) is 1530 kg

from the data given

2/3 rd of weight is over the wheel

w = 2/3rd mg

maximum force

F = \mu W

we know that F = ma

ma =  \mu (2/3 mg)

a_{max} = 2/3(1.00) (9.8) = 6.53 m/s^2

the new power is p  = 70\% P_[max} = 0.7 P_{max}

P =f_{max} v

0.7P_{max} = ma_{max} v

solving for speed v

v =0.7 \times \frac{P_{max}}{ma_{max}}

v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}

v = 11.5689 m/s

7 0
4 years ago
I really need help with this problem ;)
Nesterboy [21]

They're never the same ray.

4 0
3 years ago
Read 2 more answers
A point charge Q at the center of a sphere of radius R produces an electric flux of Φ coming out of the sphere. If the charge r
Dafna1 [17]

Remains the same

Explanation:

According to Gauss's law, the electric flux through a closed surface is proportional to the charge enclosed by the surface. So no matter how big or small we make the surface that encloses the charge, the electric flux remains the same because it only depends on the enclosed charge, not surface area.

3 0
3 years ago
A bus is designed to draw its power from a rotating flywheel that is brought up to 3000 rpm by an electric motor. The flywheel i
Arada [10]

To solve this problem we will apply the concept of rotational kinetic energy. Once this energy is found we will proceed to find the time from the definition of the power, which indicates the change of energy over time. Let's start with the kinetic energy of the rotating flywheel is

E_r = \frac{1}{2} I\omega^2

Here

I = moment of inertia

\omega = Angular velocity

Here we have that,

\omega = 3000\frac{rev}{min}(\frac{2\pi rad}{1rev})(\frac{1min}{60s})

\omega = 314.159rad/s

Replacing the value of the moment of inertia for this object we have,

E_r = \frac{1}{2} (\frac{MR^2}{2})\omega^2

E_r = \frac{1}{2} (\frac{2000(0.5)^2}{2})(314.159)^2

E_r = 1.233698*10^7J

The expression for average power is

P = \frac{E_r}{\Delta t}

\Delta t = \frac{E_r}{P}

\Delta t = \frac{1.233698*10^7}{20*10^3}

\Delta t = 616.8s \approx 620s

Therefore the correct answer is 620s.

3 0
4 years ago
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