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Helga [31]
3 years ago
12

I really need help with this problem ;)

Physics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

They are Never the same ray.

Explanation:

Hope this Helps!

Nesterboy [21]3 years ago
4 0

They're never the same ray.

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erastova [34]
Eaither D or A bit I am leaning more towards D
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3 years ago
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A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

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T = 29.6 N

5 0
4 years ago
A package is dropped from a helicopter moving upward at 15m/s. If the helicopter was 1000m above the ground when the package was
sveticcg [70]

Answer:

yi = Initial height of the helicopter

yf = final height of the helicopter

vyi = component of the initial vertical velocity of the helicopter

g = gravity constant (9.8m/s^2)

yf = yi + vyideltat - 1/2gt^2

0m = 1000m + (15m/2)deltat - 1/2(9.8m/s^2)t^2

-1000m = (15m/s)t - (-4.9m/s^2)t^2

Use the quadratic formula

4.8t^2 - 15t - 1000 = 0

t1 = 15.75s and t2 = -12.65

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Thus, it takes 15.75s before the package strikes the ground.

4 0
3 years ago
A 1.90-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. if you ignore the weight of th
gregori [183]

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The distance center of gravity from left = x

Mass on the left side = 25 kg

The distance center of gravity from right = 1.90 - x

Mass on the right side = 37 kg

At the balance point: m_1x_1=m_2x_2

25 kg\times x=37 kg\times (1.90-x)

x=1.1338 m

The center of gravity is 1.1338 m away from the left side of the barbell

7 0
4 years ago
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- A sports car travels at 180km/h. Calculate and write the steps to show how long will it travel in 40
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Answer:

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20 km

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