<span>Since the wheel start from rest. angular acceleration,
θ=1/2αt²
14=1/2α x 8.7²
α= 0.3699 rad/s²
moment of inertia of loop= mr²= 4.1x0.37=1.517 kgm²
torque=T= lα
T= 0.5611Nm= 0.56Nm to significant figure
Disc
moment of inertia of disc= 1/2mr²
Required torque value= 0.28Nm
So,
I= 1/2X 4.1X 0.37²= 0.280 Kgm²
T= Iα = 0.280 X 0.3699= 0.10 to two significant figure</span>
Answer:
259.274 kW
Explanation:
Given:
Area of the lava, A = 1.00 m²
Temperature of the surrounding, T₁ = 30.0° C = 303 k
Temperature of the lava, T₂ = 1190° C = 1463 K
emissivity, e = 1
Now,
from the Stefan-Boltzmann law of radiation the rate of heat loss is given as,
u = σeA(T₂⁴ - T₁⁴)
where,
u = rate of heat loss
σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m²∙K⁴
on substituting the respective values, we get
u = 5.67 × 10⁻⁸ × 1 × 1 × (1463⁴ - 303⁴)
or
u = 259274.957 W
or
u = 259.274 kW
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We have that the speed of the object between 60 to 70 seconds
From the question we are told
The speed of the object between 60 to 70 seconds
Generally the equation for Average speed is mathematically given as
Where
Therefore
In conclusion
The speed of the object between 60 to 70 seconds
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