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Aleksandr [31]
3 years ago
6

After 41.0 min, 41.0% of a compound has decomposed. what is the half-life of this reaction assuming first-order kinetics?

Chemistry
1 answer:
Rom4ik [11]3 years ago
6 0
<span>After 41.0 min, 41.0% of a compound has decomposed. what is the half-life of this reaction assuming first-order kinetics?</span>
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You use a _______ when you are changing compounds
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when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic
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C3H6 + Br2 → C3H6Br2

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The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

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We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

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If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume
fomenos

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c.

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A serial dilution is a dilution that is made fractionated. The stock solution is diluted, then this now solution is diluted, and then successively. The final dilution is the multiplication of the steps dilutions.

The representation of the dilution is v/v (volume per volume) indicates how much of the stock solution is in the total volume of the solution. So 1/5 indicates 1 mL to 5 mL of the solution. If the final volume must be 1 mL, then the stock solution must be 0.2 mL (0.2/1 = 1/5), and the volume of the solvent is 1 mL - 0.2 = 0.8 mL.

The second solution is done with a dilution of 1/10 or 1 mL of the first solution in 10 mL of the total solution. Because the solution has 1 mL, then the volume of the first solution must be 0.1 mL (0.1/1 = 1/10), and the volume of the solvent that must be added is 1 mL - 0.1 mL = 0.9 mL.

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