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3 years ago

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Please I neeed help, I have to write: four ammonia molecules (NH3) react with four oxygen molecules(O2) to form four nitrogen mo

noxide molecules (NO) and six water molecules. All substances are in gaseous state and heat is released in the chemical reaction

1 answer:

Dafna1 [17]3 years ago

6 0

Explanation:

the equation must be

4NH3 + 5O2–> 4NO + 6H2O

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Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc

Ber [7]

Answer:

The balanced equation for this reaction will be

$CH4 + 4F2$ → $CF4 + 4HF$

We can see that 1 mole of methane requires 4 moles of fluorine but we have 0.41 moles of CH4 and 0.56mole of F2

So using the unitary method we will get that

1 mole of CH4 → 4 mole of 4 mole of fluorine

0.41 mole of methane → 4*0.41 = 1.64 mole of fluorine for complete reaction

but we have only 0.56 mole of fluorine that means fluorine is the limiting reagent and the product will only be formed by only this amount of fluorine.

4 moles of fluorine → 1 mole of CF4

0.56 mole → $\frac{1}{4} * 0.56$ = 0.14mole of CF4

4 moles of fluorine → 4 moles of HF

0.56 mole of fluorine → 0.56 mole of HF

now to find the heat released we have the formula as

DELTA H = n * Delta H of product - n *delta H of reactant

where n is the moles of the reactant and product.

note: since no information is given about the enthalpies of the species we leave it on general equation also you need to add the product side enthalpy of the species present and similarly on the product side.

8 0

3 years ago

For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)

juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = <u>4.82 grams benzene</u>

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Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

<u>Mass CO2 = 9.15 grams</u>

4 0

4 years ago

Jill and George both push on the same cart with 20 units of force,but in opposite directions.What will happen to the cart

Anna [14]

Explanation:

It is given that, Jill and George both push on the same cart with 20 units of force, but in opposite directions.

We know that when two forces are acting in opposite direction, they cancel out each other.

Net force in this case = +20 N - 20 N = 0

It means the net force is 0. As a result, the cart will not move. The forces acting on the cart are balanced.

6 0

3 years ago

In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2

Delvig [45]

<span>2HI + Ca(OH)2 --> Cal + 2H2O. According to stoichiometry, 2 moles of HI reacts with 1 mole of Ca(OH)2. Therefore, 1.2 moles of HI will react with = 1.2/2 = 0.6 moles of Ca(OH)2. Hope this helps.</span>

7 0

3 years ago

At STP, when 3.75 liters of oxygen reacts with excess glucose, what volume of carbon dioxide does it produce?

yKpoI14uk [10]

Well, STP means standard temperature and pressure

In this condition, it is safe to assume that the moles of specie given will be equal to the moles of specie sought

I think the volume of the Carbon dioxide that it produced will also be 3.75 liters

Hope this helps

6 0

3 years ago

Read 2 more answers