Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:I think the answer is c
Step-by-step explanation:
Answer: Two and one tenth.
Answer: x=26
Explanation:
24^2+10^2= 676
Sqrt 676 = 26
Step-by-step explanation:
First
Outer
Inner
Last
First- 5x*2x=10x^2
Outer-5x*-1= -5x
Inner--7*2x= -14x
Last- -7*-1= 7
10x^2-5x-14x+7
you can simplify it further however thats the answer