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Len [333]
3 years ago
10

A barcode scanner emits a red light with frequency of 4.62x1014 s –1 . What is the wavelength of this light in nm?

Physics
1 answer:
NemiM [27]3 years ago
4 0

Answer:

 λ = 649 nm

Explanation:

given,                                    

frequency,f = 4.62 x 10¹⁴ Hz

speed of light,c = 3 x 10⁸ m/s

we know,                                      

c  = f λ                                                          

\lambda=\dfrac{c}{f}                        

\lambda=\dfrac{3\times 10^8}{4.62\times 10^{14}}

 λ = 6.4935 x 10⁻⁷ m

 λ = 649 x 10⁻⁹ m

 λ = 649 nm

the wavelength of this light is equal to 649 nm

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A bullet is dropped into a river from a very high bridge. At the same time, another bullet is fired from a gun straight down tow
anastassius [24]

Answer:

Option (c)

Explanation:

Both the bullets have same acceleration because they both falls under the influence of acceleration due to gravity.

The bullet which is fired from the gun has some initial velocity but the bullet which is dropped has zero initial velocity.

the acceleration is acting on both the bullets which is equal to the acceleration due to gravity and they both in motion in the influence of gravity.

8 0
3 years ago
I measured my pet dog (Mickey) to be able to run the length of my backyard 500 in 12 seconds. At this rate, how many miles can m
Georgia [21]

The dog runs  300240 miles.

<h3>What is the rate?</h3>

Rate refers to the pace at which something happens. We know that the easiest way to obtain the rate is by the use of proportion. Now we have been told that the dog is able to run 500 miles in 12 seconds.

If the dog runs 500 miles in 12 seconds

The dog runs x miles in 1 second

x = 500 * 1/12

x = 41.7 miles

In two hours we have 2 * 60 * 60 = 7200 seconds

If the dog runs 41.7 miles in 1 second

The dog runs x miles in 7200 seconds

x = 41.7 miles * 7200 seconds/ 1 second

x = 300240 miles

Learn more about proportion:brainly.com/question/2548537

#SPJ1

4 0
2 years ago
Calculate the elastic potential energy stored in a spring if it has a force constant of 150 N/m. the spring is extended to a len
Alenkinab [10]

Answer:

6.75J

Explanation:

U=1/2KΔx²

U=0.5* 150*0.30^2

4 0
2 years ago
An 80-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles.
ivann1987 [24]

Answer:

The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.

Explanation:

To answer this question, let's write Newton's second law of the two axes

Y Axis  

        Fy + N - W = 0

        Fy + N = W

X axis

       Fx - fr = 0

      Fx = fr

The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.

   The direction of this force is along the length of the rods that are in an Angle, where the x and y components of the force come from

In general this force is small because the rubbing of the skis is small

8 0
3 years ago
How much water will flow in 30 secs through 200 mm of capillary tube of 1.50 mm in diameter, if the pressure difference across t
Paladinen [302]

The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as

Qo=1.6 \times 10^{2} \mathrm{~mL}

<h3>What is the water outflow in 30 secs through 200 mm of the capillary tube?</h3>

\begin{aligned}\Delta P &=6660 \mathrm{~m} / \mathrm{m}^{2} \\\mu &=8.01 \times 10^{-4} \text { Pas } \\t &=30 \mathrm{~s} \\L &=200 \mathrm{~mm}=200 \times 10^{-3} \mathrm{~m} \\D &=1.5 \mathrm{~mm}=1.5 \times 10^{-3} \mathrm{~m} \Rightarrow \gamma=\frac{1.5 \times 10^{-3}}{2} \mathrm{~m}\end{aligned}

Generally, the equation for Rate of flow of Liquid is  mathematically given as

\\$$Q=\frac{\pi r^{4} \times \Delta P}{8 \mu L}

$$

Where dP is pressure difference r is the radius

\mu is the viscosity of water

L is the length of the pipe

Q=\frac{\pi \times\left(\frac{1.5 \times 10^{-3}}{2}\right)^{4} \times 6660}{8 \times 8.01 \times 10^{-4} \times 200 \times 10^{-3}}

Q=5.2 \mathrm{~mL} / \mathrm{s}

In $30s the quantity that flows out of the tube

&Qo=5.2 \times 30 \\&Qo=1.6 \times 10^{2} \mathrm{~mL}

In conclusion, the quantity that flows out of the tube

Qo=1.6 \times 10^{2} \mathrm{~mL}

Read more about the flows rate

brainly.com/question/27880305

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5 0
1 year ago
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