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iVinArrow [24]
3 years ago
11

Are the ratios of free throws made to free throws attempted by the rockets and by the turbos equivalent?

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

<h2>No, they're not equivalent.</h2>

Step-by-step explanation:

In the image attaches you can observe the Free Throws Made and the Free Throws Attempted.

Team Rockets Made 8 Free Throws, and Attempted 24, which give a ratio of

R=\frac{8}{24}=\frac{1}{3}

Team Turbos Made 16 free throws and attempted 36, which give a ratio of

T=\frac{16}{36}=\frac{8}{18} =\frac{4}{9}

As you can see, the ratio are diferent.

Therefore, the ratios are not equivalent.

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Which quadrilaterals do not have parallel sides? rhombus trapezoid quadrilateral isosceles trapezoid
OLEGan [10]
So what is a quadrilateral something that has four sides. So as long as the sides DON't intersect they're fine but. A rhombus is parallel the sides won't cross. Trust me, this is a rush job. a trapezoid has only ONE parallel side but is it still parallel? It's the last option.<span />
7 0
3 years ago
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The cost of making a shirt is half of what the shirt normally sells for. Today, the shirt is in a 15 percent discount from its n
Vaselesa [24]

Answer:

.85 times the cost to make the shirt

Step-by-step explanation:

Let x represent cost to make the shirt.

Today, the shirt is in a 15 percent discount from its normal price.

Discount = 15/100 * x = 0.15x

Current cost = Original cost - discount

Current cost = x - 0.15x = 0.85x

The answer is;

.85 times the cost to make the shirt

4 0
3 years ago
If the vertices of a right triangle are located at (2,6), (2,3), and (6,3), what is the length of the hypotenuse?
Sergio [31]

Answer:

5 units

Step-by-step explanation:

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7 0
3 years ago
Plz help i got to go in 10 min
AlexFokin [52]
I think it’s 390. I hope I’m not too late :V
4 0
4 years ago
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Please try your best and show your work and I will give brainliest!
dimulka [17.4K]

Answer:

Part A: impossible

Part B: Either equal or blue

Part C: 9 green and 2 blue were added

Step-by-step explanation:

Part A:

The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.

Part B:

I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.

Part C:

The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.

I hope this helps and please mark me as brainliest!

5 0
2 years ago
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