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3 years ago

10

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dn-cgi/l/email-protection" class="__cf_email__" data-cfemail="33121212121273">[email protected]%@!!!!!!!!

1 answer:

Step2247 [10]3 years ago

3 0

1.36 < sqrt(2) < 2.45

1.65 < sqrt(3) < 2.34

1.65 < sqrt(4) < 2.34

1.65 < sqrt(5) < 2.34

1.53 < sqrt(6) < 2.46

feel like several of these are wrong sorry

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A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final leng

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Answer:

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Step-by-step explanation:

The Poisson's ratio ( $\nu$ ), no unit, is the ratio of transversal strain ( $\epsilon_{t}$ ), in inches, to axial strain ( $\epsilon_{a}$ ), in inches:

$\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}$ (1)

$\epsilon_{a} = l_{a,f}-l_{a,o}$ (2)

$\epsilon_{t} = l_{t,f}-l_{t,o}$ (3)

Where:

$l_{a,o}$ - Initial axial length, in inches.

$l_{a,f}$ - Final axial length, in inches.

$l_{t,o}$ - Initial transversal length, in inches.

$l_{t,f}$ - Final transversal length, in inches.

If we know that $l_{a,o} = 61.2\,in$ , $l_{a,f} = 61.235\,in$ , $l_{t,o} = 2.7\,in$ and $l_{t,f} = 2.69953\,in$ , then the Poisson's ratio is:

$\epsilon_{a} = 61.235\,in - 61.2\,in$

$\epsilon_{a} = 0.035\,in$

$\epsilon_{t} = 2.69953\,in - 2.7\,in$

$\epsilon_{t} = -4.7\times 10^{-4}\,in$

$\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}$

$\nu = 0.0134$

The Poisson's ratio for the material is 0.0134.

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Step-by-step explanation:

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