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Alona [7]
3 years ago
7

The molality of a solution that was made by dissolving NaCl in 1.5 kg of water is 0.40 m. If the molar mass of NaCl is 58.44 g/m

ol, what is the mass of NaCl that was dissolved?
0.27 g
23 g
35 g
39 g
Chemistry
2 answers:
kirill115 [55]3 years ago
8 0

Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the mass of the solute in a given solution, we need to calculate first for the number of moles of the substance by the product of the molality and the mass of the solvent. Then, we convert the number of moles into mass by using the molar mass. <span>
</span>

moles NaCl = 0.40 m (1.5 kg water) = 0.6 mol NaCl

mass NaCl = 0.6 mol NaCl ( 58.44 g / mol ) = 35.06 g NaCl

Therefore, the correct answer would be the third option.

lesya692 [45]3 years ago
5 0

Answer: SEE

Explanation: C

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I have attached the structure of Butanoic Acid. Please refer to the attachment.

Explanation:

Solution:

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3 years ago
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Explanation:

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