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Jet001 [13]
2 years ago
6

Can you help please?

Chemistry
1 answer:
Aneli [31]2 years ago
3 0

Answer:

In this reaction, 38.1 grams of copper will be produced.

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226<br> ) Which equation represents the radioactive decay of Ra?<br> 88
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i think the answer is b

Explanation:

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3 years ago
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Does deforestation cause the amount of carbon dioxide in the air to increase or decrease?
oee [108]

Answer:

Explanation:

Deforestation has an adverse affect on air by reducing the amount of oxygen and increasing the amount of carbon dioxide as well as contributing to global warming.

4 0
3 years ago
24. The only thing that Carbon, nitrogen and oxygen want is
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To bond with another atom
7 0
3 years ago
Express the equilibrium constant for the following reaction.P4O10(s) ↔ P4(s) + 5 O2(g)K = [P4][O2]^5/[P4O10]K = [O2]^5K = [P4O10
Alex17521 [72]

Answer : The correct expression for equilibrium constant will be, K=[O_2]^5

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

P_4O_{10}(s)\rightleftharpoons P_4(s)+5O_2(g)

The expression of K will be,

K=[O_2]^5

Therefore, the correct expression for equilibrium constant will be, K=[O_2]^5

7 0
4 years ago
14.7 grams of magnesium reacts completely with 9.7 grams of oxygen to form magnesium oxide (MgO). What is the percent compositio
swat32
The answer is 60.3% magnesium, 39.7% oxygen.
Solution:
The chemical equation for the reaction is 2 Mg + O2 → 2 MgO.
Since magnesium reacts completely with oxygen, it is the limiting reactant in the reaction. Hence, we can use the number of moles of magnesium to get the mass of MgO produced:
     moles of magnesium = 14.7g / 24.305g mol-1
                                       = 0.6048 mol

     mass of MgO = 0.6048mol Mg(2 mol MgO/2mol Mg)(40.3044g MgO/1 mol MgO) 
                           = 24.376g MgO

We can now solve for the percentage of magnesium:
     % Mg = (14.7g Mg / 24.376g MgO)*100% = 60.3%

We also use the number of moles of magnesium to get the mass of oxygen consumed in the reaction:
     mass of O2 =  0.6048 mol Mg (1mol O2 / 2mol Mg) (31.998g / 1mol O2) 
                        = 9.676g

The percentage of oxygen is therefore
     % O2 = (9.676g O2 / 24.376g MgO)*100%
               = 39.7%
Notice that we can just subtract the magnesium's percentage from 100% to get 
     % O2 = 100% - 60.3% = 39.7%
5 0
3 years ago
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