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cluponka [151]
2 years ago
11

How many sodium ions are contained in 99.6 mg of na2so3? The molar mass of na2so3 is 126.05 g/mol.

Chemistry
2 answers:
marin [14]2 years ago
8 0
The answer is D shadowing
Norma-Jean [14]2 years ago
3 0

Answer:

9.52x10²⁰ sodium ions

Explanation:

First, we need to convert the mass in moles (n)

n = mass/molar mass

The moalr mass is given in g/mol, so let's transform the mass in gram:

1 g ------------ 1000 mg

x g------------- 99.6 mg

By a direct simple three rule:

1000x = 99.6

x = 0.0996 g

n = 0.0996/126.05

n = 7.90x10⁻⁴ mol of Na₂SO₃

The ionization reaction is:

Na₂SO₃ → 2Na⁺ + SO₃⁻

So, for 1 mol of Na₂SO₃, will be two moles of Na⁺ (sodium ion), then:

1 mol of Na₂SO₃ --------------- 2 moles of Na⁺

7.90x10⁻⁴ ------------------------- x

By a simple direct three rule:

x = 1.58x10⁻³ mol of Na⁺

Avogadro has related the number of moles with the number of the matter: atoms, ions, molecules. So, 1 mol has 6.02x10²³ ions.

1 mol ------------------- 6.02x10²³

1.58x10⁻³ mol ----------- x

By a direct simple three rule:

x = 9.52x10²⁰ sodium ions

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B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
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Please help!! i need the answer ASAP!
nirvana33 [79]

Answer:

23.34 %.

Explanation:

  • The percentage of water must be calculated as a mass percent.
  • We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.
  • <em>Atomic masses of the elements:</em>

Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.

  • <em>Mass of the formula unit:</em>

Cd(NO₃)₂•4H₂O

mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.

  • <em> Mass of water in the formula unit:</em>

<em>mass of water</em> = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.

  • <em>So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %</em>
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2 years ago
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