The following illustration <span>contains the stoichiometric quantities of the reactants for this reaction.
</span><span>In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). </span><span>The reaction is as follows :
N</span>
+
=
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
Answer:
Mass of hydrogen = 667 kg (Approx)
Explanation:
Given:
Mass of water = 593 kg
Yield rate = 88.9%
Find:
Mass of hydrogen
Computation:
Mass of hydrogen = [Mass of water / Yield rate]100
Mass of hydrogen = [593 / 88.9]100
Mass of hydrogen = 667.04162
Mass of hydrogen = 667 kg (Approx)
Given that the metal is reactive, like magnesium is, the ions of the metal displace the hydrogen ions released by the acid and the metal ions combine with the acid's anions, forming a salt. The displaced hydrogen ions are released in the form of hydrogen gas. The reaction equation is as follows:
Acid + metal → salt + hydrogen gas
Answer:
Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... The rest of the bonds all contain electrons from both hydrogen and nitrogen, so they would be considered ordinary covalent bonds.
Answer:
16.4 L
Explanation:
we can use the combined gas law equation that gives the relationship among volume, temperature and pressure conditions of gases.
P1V1/T1 = P2V2/T2
STP conditions are standard temperature and pressure conditions
P1 is standard pressure = 1 atm , T1 is standard temperature = 273 K
and V1 is the volume
P2 is pressure, T2 is temperature and V2 is volume at the second instance
temperature is in kelvin scale,
512 ° + 273 = 785 K
substituting the values in the equation
1 atm x 10.0 L / 273 K = 1.75 atm x V / 785 K
V = 16.4 L
new volume is 16.4 L
