A. The Dawes limit tells
us that the resolving power is equal to 11.6 / d, where d is the diameter of
the eye’s pupil in units of centimeters. The eye's pupil can dialate to approximately
7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc
minute ~ 17 arc seconds<span>
Although, the standard answer for what people can really see
is about 1 arc minute.
</span>
<span>
B. It is considered as linear, so given a 10 meter telescope
(10,000 mm): </span>
10000 / 7 = 1428 times
better for the 10 meter scope ~ 1400 times better (in 2 significant figures)
<span>
<span>C. For a 7 cm interferometer, that is just similar to a 7 cm
scope. Therefore we would expect </span></span>
<span><span>11.6 / 7 = 1.65 arc seconds ~ 1.7 arc seconds</span></span>
<span><span>T</span></span>his value is what
we typically can get from a 7 cm scope.
I there supposed to be a picture here or
Answer:
-8.04 m/s2
Explanation:
To find the answer to this, you have to use the 4th kinematic equation:
You plug into the equation to get:
solve for a to get
-8.04 m/s2
im sorry but i dont know, good luck at finding someone else who does.
Answer:
The work done by the gravel to stop the truck is 520.44 kJ
Explanation:
<u>Step 1</u>: Data given
Mass of the truck = 3047.8 kg
The ramp has an angle of 9.5 °
Velocity of the truck = 20.68 m/s
distance = 26.6 meters
<u>Step 2:</u> Calculate initial kinetic energy
sin 9.5° = 0.165
h = ℓ*sin 9.5° = 26.6*0.165= 4.39 m
Ek = 1/2m*Vo² = 1/2*3047.8*20.68² = 651714.7 Joule = 651.7 kJ = initial kinetic energy
<u>Step 3: </u>Calculate potential energy
Epot = U = m*g*h = 3047.8*9.81*4.39 = 131256.25 Joule = 131.26 kJ
<u>Step 4:</u> What work is done by the truck on the gravel?
Frictional energy Ef = 651.7 kJ - 131.26 kJ = 520.44 kJ
