1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stiv31 [10]
3 years ago
13

??????????????????????????????

Physics
1 answer:
Reptile [31]3 years ago
6 0

Answer: its C

Explanation:

You might be interested in
Three identical resistors are connected in parallel to a battery. If the current of 12. A flows from the battery, how much curre
Doss [256]

Answer:

4 A

Explanation:

We are given that

R_1=R_2=R_3=4\Omega

I=12 A

We have to find the current flowing through each resistor.

We know that in parallel combination current flowing through different resistors are different and potential difference across each resistor is same.

Formula :

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

Using the formula

\frac{1}{R}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{3}{4}

R=\frac{4}{3}\Omega

V=IR

Substitute the values

V=12\times \frac{4}{3}=16 V

I_1=\frac{V}{R_1}=\frac{16}{4}=4 A

I_1=I_2=I_3=4 A

Hence, current flows through any one of the resistors is 4 A.

7 0
3 years ago
a school bus has stopped to allow children to get off the bus which graph shows the motion of the bus?​
Usimov [2.4K]

Answer: what is it in

Explanation:

4 0
3 years ago
In which changes of state do atoms lose energy
Anika [276]
             Yeah, it's every state. Atoms need a certain quanta of energy to jump to each state of energy, and therefore change state depending on how much energy is absorbed and/or released. This applies to all states of matter.        
6 0
3 years ago
A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.
Salsk061 [2.6K]

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= \frac{1}{2}(m*v^{2})

where v = velocity

          m= mass

therefore,               v=\sqrt\frac{2*K.E}{m} {}

                         or,  v=\sqrt{\frac{2*258720}{2200} }

                         or,   v=15.33 m/s

7 0
3 years ago
I need HELP Please !!
aliya0001 [1]
You have to figure it out
5 0
3 years ago
Other questions:
  • Consider the circuit below, which is powered by a 6-v battery. switch s is opened at t = 0 after having been closed for a long t
    13·1 answer
  • The density of gold is 19.3 g/cm^3. what is the mass of 24 cm^3 of gold?
    9·1 answer
  • When a star goes from the main sequence to the red giant phase, it becomes larger rather than smaller. This is true because grav
    7·1 answer
  • A 55.6-kg skateboarder starts out with a speed of 2.44 m/s. He does 80.4 J of work on himself by pushing with his feet against t
    9·1 answer
  • How long does it take for carbon to become a fossil fuel
    13·2 answers
  • A garden hose with an internal diameter of 2.9 cm is connected to a (stationary) lawn sprinkler that consists merely of a contai
    15·1 answer
  • Observations of the Crab Nebula taken over several decades show that gas blobs that are now 100 arcseconds from the center of th
    10·1 answer
  • Which elements will have chemical properties similar to NE (neon)?
    15·1 answer
  • When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g
    6·1 answer
  • A different group is worried that the motion detector will not
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!