Answer:
Explanation:
Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.
To objective is to find the:
(i) required heat exchanger area.
(ii) flow rate to be maintained in the evaporator.
Given that:
water temperature = 300 K
At a reasonable depth, the water is cold and its temperature = 280 K
The power output W = 2 MW
Efficiency
= 3%
where;



However, from the evaporator, the heat transfer Q can be determined by using the formula:
Q = UA(L MTD)
where;

Also;




LMTD = 4.97
Thus, the required heat exchanger area A is calculated by using the formula:

where;
U = overall heat coefficient given as 1200 W/m².K

The mass flow rate:

Answer:
This is something for biology, it shouldnt be in the physics subject
Explanation:
Answer:
2 m/s²
Explanation:
a = Δv / Δt
a = (3 m/s − 1 m/s) / 1 s
a = 2 m/s²
Answer:
tension is 0.692 N
magnetic force is 0.401 N
Explanation:
given data
mass = 57.5 g = 0.0575 kg
long = 38.8 cm = 0.388 m
displace = 22.5 cm = 0.225 m
to find out
free-body diagram , tension and magnetic force
solution
we consider here angle is θ
so free body diagram is attach below
and
here cosθ = x/l
so θ = cos^-1 ( 0.225 / 0.388)
θ = 54.6°
so tension from net force is
net vertical force
t sinθ - F(g) = 0 ...........1
t = F(g) / sinθ
t = mg /sin54.6
t = 0.0575 ( 9.8) / sin54.6
t = 0.692
so tension is 0.692 N
and
net horizontal force
- t cosθ + F(magnetic) = 0 ....................2
t cosθ = F(magnetic)
put here all value
F(magnetic) = 0.692 × cos 54.6
F(magnetic) = 0.401
so magnetic force is 0.401 N
Choice (3) would be one of the objects because when its stretching its waiting to release the energy. Then choice (1) would be the other object because when it rolls the energy stored in the ball would be released when stopped. Therefore there storing the energy until released.