The expression rt can be used to find the distance traveled by an object that has an average speed of r overtime t. How many mil
1 answer:
Answer:
So then after 2.2 hours with an average speed of 12.5 mi/hr the hot air ballon will travel 27.5 mi
Step-by-step explanation:
For this problem we know that the distance traveled by an object is given by:
(1)
Where d is the distance r the average speed and t the time.
From the info given we know that and
And replacing into formula (1) we got:
So then after 2.2 hours with an average speed of 12.5 mi/hr the hot air ballon will travel 27.5 mi
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Answer:
c = 15d + 30
Step-by-step explanation:
Hey there!
This can be represented by an equation of a line, where the number of days is our x-values(d), and the price is our y-values(c).
The price for one day ($45) and the price for 4 days($90) are specific points on that line.
The points are (1, 45) and (4, 90).
We can first find the slope of the line:
- As the price rises 45, the days increase by 3
- Slope = rise/run
- Slope = 45/3
- Slope = 15
Now we can find the base price, by plugging the slope and a point into the equation y = mx + b.
Solve for b:
- y = mx + b
- 45 = 15(1) + b
- 45 = 15 + b
- 30 = b
The base price (b) is 30.
The equation is
Answer:
15.15% probability that the sample mean will be $192,000 or more.
Step-by-step explanation:
To solve this problem, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
The probability that the sample mean will be $192,000 or more is
This is 1 subtracted by the pvalue of z when X = 192000. So
By the Central Limit Theorem
has a pvalue of 0.8485.
1-0.8485 = 0.1515
15.15% probability that the sample mean will be $192,000 or more.