Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Answer: sksijjenenenwkkwkw
Answer:
320
Step-by-step explanation:
6400 x minute = 6400/60 = 106.66666666666666666666666666667 ft/h
*3=320ft
320ft to miles = 0.0606061
Answer:
-2r-19p
Step-by-step explanation:
-4p-2r-15p
add like terms
-2r-19p
