4 years ago

How does place value help me divide

1 answer:

3 0

Because, when you divide you can use place value to break the equation up and make it easy. Example: 142/2. 140/2=70 and 2/2=1 add 70 +1=71. So 142/2=71

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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Phantasy [73]

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^{\circ}-q)=\cos 180^{\circ} \cos (q)+\sin q \sin 180^{\circ}$

Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

7 0

4 years ago

Read 2 more answers

Evaluate the expression 8x - 10 when x = 4

serg [7]

Answer: 8(4) - 10 equals to 22 :)

4 0

3 years ago

Read 2 more answers

The cost of a student ticket to the schools play is $7. write an equation that correctly relates the cost,c,for particular numbe

charle [14.2K]

The independent variables are the cost for one ticket and the number of student tickets. The cost of the tickets depends on the number of student tickets being purchased. The equation would be c = 7s.

4 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7Bx%7D%20%2B%5Cfrac%7B2%7D%7Bx%7D%20%3D12" id="TexFormula1" title="\frac{10

Ber [7]

I guess that the most obvious answer is

x = 1

8 0

4 years ago

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Which of the following best describes the relationship between (x + 2) and

Troyanec [42]

Answer:

B. (x+2) is a factor

Step-by-step explanation:

3x^2 -x-14

3x^2+6x-7x-14

3x(x+2)-7(x+2)

(3x-7)(x+2)

so, x+2 is a factor of 3x^2-x-14

8 0

4 years ago