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Aleonysh [2.5K]
3 years ago
10

A student has two compounds in two separate bottles but with no labels on either one. One is an unbranched alkane, octane, C8H18

; the other is 1-hexene, an unbranched alkene, C6H12. Based on your observations in this experiment, tell what you should see in the following tests: (a)- Water solubility (b)- Ligroin solubility (c)- Combustion (d)- Density versus water (e)- Bromine test (f)- Permanganate test
Chemistry
1 answer:
Aleks [24]3 years ago
7 0

Answer:

a) both substances are insoluble in water

b) both substances are soluble in ligroin

c) both substances suffer combustion, octane produces more CO₂ than hexene.

d) both substances are less dense than waterl, with hexene having the lowest density.

e) only hexene would react with bromine

f)  only hexene would react with permanganate

Explanation:

a) both substances are non-polar and water is polar

b) both substances are non-polar and lingroin is non-polar

c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O

    C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

d) water = 997 kg/m³

    ocatne = 703 kg/m³

    hexene = 673 kg/m³

e) bromine test is used to detect unsaturations

f) permanganate test is used to detect unsaturations

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Answer:

21.3 g of CaCl₂ are produced in this reaction

Explanation:

Reaction is this:

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We have 14 g / 36.45 g/m = 0.384 moles of HCl

Ratio is 1:2, so 0.279 moles of salt will need the double of moles of acid.

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Molar mass of CaCl₂ = 110.98 g/m

Mol . molar mass = mass → 0.192 m . 110.98 g/m = 21.3 g

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Answer:

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Explanation:

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